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brilliants [131]
1 year ago
4

A company has a target to reduce the number of its stores by 40% over the next two years. At the end of the first year it has re

duced the number of its stores by 20% If the company is going to reach its target, it must reduce the number of its stores
Mathematics
1 answer:
lilavasa [31]1 year ago
3 0

Answer:

by 25%

Step-by-step explanation:

We can assume that the company originally had 100 stores and it plans to keep only 60 open after two years. If it was able to close 20 stores during the first year, the total number of stores remaining open was 100 - 20 = 80. Since it needs to decrease the number of stores to 60, it must reduce the number of stores by 20/80 = 0.25 or 25%.

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On jeopardy there are 5 monetary categories- $100 $200 $300 $400 and $500. Each of them have an equally likely chance of popping
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Suppose S is a recursively defined set, defined by the number 1 is in S if n is in S, then so is 3n+2 - if n is in S, then so is
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That the number 1 has this property.

Step-by-step explanation:

For base step we have to prove that number 1 has the property.

so therefore the smallest number of S is 1.

So that the number 1 has this property.

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2 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
2 years ago
suppose the commute times for employees of a large company follow a normal distribution. if the mean time is 18 minutes and the
stepladder [879]

Answer:I think A

Step-by-step explanation:

Hopefully I am right

4 0
2 years ago
Read 2 more answers
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