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Aleks [24]
1 year ago
14

What single percentage change is equivalent to a 13% decrease followed by a 19% decrease?​

Mathematics
1 answer:
Mrac [35]1 year ago
6 0
Answer: 70.47%

100% - 13% = 87%

19% of 87% = 16.53%

remaining percent
= 87% - 16.53%
=70.47%
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A person is standing 50 ft from a statue. The person looks up at an angle of elevation of 8o when staring at the top of the stat
Lyrx [107]

Answer:

h=50.25\ ft

Step-by-step explanation:

<u>Right Triangles </u>

In a right triangle, one of the internal angles is 90°. When this happens, there is always a longer side, called hypotenuse and two shorter sides, called legs. They relate to Pythagoras's theorem. The basic trigonometric relations also stand, including

\displaystyle tan\alpha=\frac{a}{c}

where a is the opposite leg to \alpha and c is its adjacent led .

In our problem, we have a statue being looked by a person in such a way that the top of the statue forms an angle of 8° with the horizontal and the base of the statue forms an angle of 14° down. We also know the distance from the person to the statue is 50 ft. The situation is shown in the image below.

The height of the statue is h=a+b, where

a=50tan8^o

b=50tan14^o

Thus

h=50tan8^o+50tan14^o

h=50(tan8^o+tan14^o)

\boxed{h=50.25\ ft}

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2 years ago
A chef makes 3 containers of soup that fill a total of 120 soup bowls. Each container of soup costs $30 to make. What is the cos
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What is the multiplicative rate of change of the function described in the table ?
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The answer to the question is B.
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Tyrone paid $234.33 for a new watch, after tax, and the tax rate is 7%. What was the original price of the watch?
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2 years ago
A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes
marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

V = s^2h = 5324

h = 5324 / s^2

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top s^2

Side area 4sh

Total surface area A = s^2 + 4sh

We can substitute h = 5324 / s^2

A = s^2 + 4s\frac{5324}{s^2}

A = s^2 + 21296/s

To find the minimum of this function, we can take the first derivative, and set it to 0

A' = 2s - 21296/s^2 = 0

2s = 21296/s^2

s^3 = 10648

s = \sqrt[3]{10648} = 22

h = 5324 / s^2 = 5324 / 22^2 = 11

4 0
2 years ago
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