Answer:
It destroy both harmful and beneficial microbes.
Explanation:
If scientist added a chemical to destroy the arctic microbes, the beneficial as well as harmful microbes also eliminated from that area where chemical is applied. The removal of harmful microbes is a good thing but the removal of beneficial microbes brings instability in the environment. These beneficial microbes helps in the recycling of nutrients for the plants present there. So the negative effect of chemical is that it also effect the beneficial microbes which are necessary for the ecosystem.
Answer:
B, G , E, F.
Explanation:
Hemoglobin is known to be a tetrameric hemeprotein, which is found in the erythrocytes where it binds with oxygen,and then the bound oxygen is transported to parts of the body.
Myoglobin is a monomeric protein that is found in the muscle tissue. Its function is that, it serves as intracellular storage site for oxygen.
It should be understood that, both hemoglobin and myoglobin are hemeproteins with physiological importance of having the ability of binding molecular oxygen.
In this case, it is also known that, the two, that is hemoglobin and myoglobin have a prosthetic group called heme, which is described or known to be a tightly bond, specifically a non-polypeptide unit which is required for biological function of some protein.
Answer:
It would just be transmitted to DNA
Explanation:
Answer:
2% of the progeny will be double crossovers for the trihybrid test cross
Explanation:
By knowing the positions of genes, we can estimate the distances in MU between them per region.
- Genes A and B are 10 map units apart (Region I)
- Genes B and C are 20 map units apart (Region II)
- Genes A and C are 30 map units apart
----A-------10MU--------B-------------20MU-------------C---
Region I Region II
We can estimate the recombination frequencies by dividing each distance by 100.
• recombination frequency of A-B region = 10MU / 100 = 0.10
• recombination frequency of B-C region = 20MU / 100 = 0.20
Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:
EDRF = recombination frequency in region I x recombination frequency in region II.
EDRF = 0.10 x 0.20 = 0.02
2% of the progeny will be double crossovers for the trihybrid test cross
