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2 years ago

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Rachel is pouring a concrete patio. Her patio will be 6 inches deep, 6 feet long and 8 feet wide. If she rounds up to the neares

t hundredth, how many cubic yards of concrete will she need? (Remember, yd3=in3÷46,656 )

1 answer:

zzz [600]2 years ago

4 0

Answer:

2.6667yd^3

Step-by-step explanation

Volume of the concrete = Length * width * height

Given

height = 6 inches

To yards;

1 in = 0.0277778yd

6 in = 6 * 0.0277778

6in = 0.1666668 yards

Width = 8 feet

Length = 6ft

LW = 48ft²

To yards;

1 ft = 0.333333yd

48 ft = 48(0.333333)

48 ft^ 2 = 15.999984yd^2

Volume = 15.999984 * 0.1666668

Volume = 2.6667 yd^3

Hence she will need 2.6667yd^3 concrete

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So the question tells to express the expression in your problem where N0 is N-naught and the symbol represent the lower case Greek letter lambda. So the best answer or expression would be that the lambda is the wavelength of the expression. I hope you are satisfied with my answer

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A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 1.5 feet, 30 feet a

Nimfa-mama [501]

Answer:

x₁ > x₂

Step-by-step explanation:

Both actions imply a parable trajectories, since both are projectile shot cases.

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In the second case, the parable curve is modeled by:

y = x₂*( 0.08 - 0.002x₂) or y = 0.08*x₂ - 0.002*x₂²

A second degree equation, solving for x₂ and dismissing the value x₂ = 0

we get:

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2 years ago

Suppose you have just enough money, in coins, to pay for a gallon of milk priced at $2.40. You have 12 coins, all quarters and d

wel

The answer is
q + d = 12
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d - the number of dimes

You have 12 <span>coins, all quarters and dimes:
q + d = 12

The value of 1 quarter is $0.25.
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2 years ago

The sales data for January and February of a frozen yogurt shop are approximately normal. The mean daily sales for January was $

VashaNatasha [74]

Answer:

January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

Step-by-step explanation:

z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

January:

The mean daily sales for January was $300 with a standard deviation of $20. On the 15th of January, the shop sold $310 of yogurt. This means, respectively, that $\mu = 300, \sigma = 20, X = 310$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{310 - 300}{20}$

$Z = 0.5$

February:

The mean daily sales for February was $320 with a standard deviation of $50. On the 15th of February, the shop sold $340 of yogurt. This means, respectively, that $\mu = 320, \sigma = 50, X = 340$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{340 - 320}{50}$

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January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

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2 years ago

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Tresset [83]

Answer:

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Step-by-step explanation:

Given : For the sequence $a_n= 2^n + 1$

To find : Identify the values of following?

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The nth term of the sequence is $a_n= 2^n + 1$

Substitute n=0,1,2 and 3

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$a_0= 2^0+ 1$

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$a_0=2$

When n=1,

$a_1= 2^1+ 1$

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When n=2,

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$a_2=5$

When n=3,

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$a_3= 8+ 1$

$a_3= 9$

Therefore, The value is $a_0= 2,a_1= 3,a_2= 5,a_3= 9$

So, Option A is correct.

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2 years ago