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lubasha [3.4K]
2 years ago
6

a solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned

his electric heat on, the excess be used up at 50 kilowatts hours per day
Mathematics
1 answer:
Jlenok [28]2 years ago
4 0

Question:

A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .

(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d

(b) How much of excess will be left after one month (1 month = 30 days)

Answer:

a. E = 6500 - 50d

b. E = 5000

Step-by-step explanation:

Given

Excess = 6500kwh

Rate = 50kwh/day

Solving (a): E in terms of d

The Excess left (E) in d days is calculated using:

E = Excess - Rate * days

The expression uses minus because there's a reduction in the excess kwh on a daily basis.

Substitute values for Excess, Rate and days

E = 6500 - 50 * d

E = 6500 - 50d

Solving (b); The value of E when d = 30.

Substitute 30 for d in E = 6500 - 50d

E = 6500 - 50 * 30

E = 6500 - 1500

E = 5000

<em>Hence, there are 5000kwh left after 30 days</em>

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Answer:

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2 years ago
Mario has a business selling muffins. Let x be the price of a muffin. Then, the profit P for Mario’s business is given by p(x)=-
Rufina [12.5K]
To make a positive profit p(x)>0 we need to make:
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We have:
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We will use formula for quadratic equation:
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Fatima Sheroud sells children’s clothing for The Grasshopper Shoppe. She is paid weekly on a straight commission of 4% on sales
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owen and needed to get his computer fixed he took it to the repair store the technician at the store worked on the computer for
meriva

To figure out this problem, let's set up an equation first to make it easier:

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702.50 = 5.5x + 70

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-----------------------------

632.5 = 5.5x

/5.5       /5.5

--------------------

115   =   x

Owen was charged $115 per hour

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