* Craig's answer is not reasonable because to add fractions the denominators must be the same.
** Total distance = 5/8 + 1/2 = 5/8 + 4/8 = 9/8 miles
*** Using the line number to prove the answer:
The line number that represents the problem is in the attached figure.
while the distance between 0 and 1 divided to 8 sections
to represent (5/8) count 5 sections from zero ⇒⇒⇒ point (a)
and to represent (1/2) it is the midpoint between 0 and 1 which mean it is 4 sections but it will be counted from point (a) so, adding 4 sections to point (a) the result will be the point (b)
So, counting from 0 to point (b) will give us 9 sections
and while one section represents (1/8)
So the total distance will be 9 * (1/8) = 9/8 which is agree with the result obtained before
In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66. What
julia-pushkina [17]
Answer:
The 65th percentile is between 73 and 74
Step-by-step explanation:
Rearrange the ungrouped data in ascending order: 65,66,67,68,71,73,74,77,77,77
The 65th percentile is 65/100 of N ( N = 10) = 65/100 × 10 = 6.5
The 65th percentile is the 6.5th term. The 6th term is 73 and the 7th term is 74, the 6.5th term is between the 6th and 7th term
The 65th percentile is between 73 and 74
<span>Plato explains that we know geometry by our gain knowledge through recollection. Our soul is what recollects this place hence we came where there exist unchanging truths. Delivered the theory of Forms, according to which the world people know by means of the senses is just an imitation of the eternal, pure, eternal, and fixed world of the Forms.</span>
Answer:
Year in which the entrepreneur break even is 4
Step-by-step explanation:
We are given:
p(x) = x^3-4x^2+5x-20
We would find the value of x
Solving:
x^3-4x^2+5x-20 = 0
(x^3-4x^2)+(5x-20) = 0
x^2(x-4)+5(x-4) = 0
(x-4)(x^2+5)=0
=> x-4 = 0 and x^2+5 =0
x = 4 and x^2 = -5
x = 4 and x = ±√-5 or ±√5 i (not real solutions)
So, x = 4
So, year in which the entrepreneur break even is 4
His equation could be written in quadratic form, which is ax^2+bx=c