Ask question

Ask question

All categories

2 years ago

7

A recipe for sparkling grape juice calls for 1 1/2 quarts of sparkling water 3/4 quart of grape juice. Q1: How much sparkling wa

ter would you need to mix with 9 quarts juice? Q2: How much grape jucie would you need to mix 15/4 quarts of sparkling water ? Q3: How much of each ingredient would you need to make 100 quarts of punch?

1 answer:

kogti [31]2 years ago

3 0

Answer:

1) 18 Quart of Sparkling water need to mix with 9 quart grape juice

2) 15/2 Quart of grape juice required for 15/4 quarts of sparkling water.

3) Quantity of grape juice and sparkling water in 100 quart of punch are 33 1/3 quart and 66 2/3 quart respectively.

Step-by-step explanation:

1 1/2 quarts = 1 + (1/2) = 3/2 quarts

1) water required for 3/4 quart of grape juice = 3/2 quarts

so water required for 1 quart of grape juice = (3/2) ÷ (3/4) = (3/2)× (4/3) = 2 quarts

so water required for 9 quart of grape juice = 9 * 2 = 18 quart

18 Quart of Sparkling water need to mix with 9 quart grape juice

2) From solution of 1 ,

For 18 quart of Sparkling water , grape juice require = 9 quart

So for 1 quart of Sparkling water , grape juice require = 9÷18 = 1/2 Quart

so for 15/4 quart of Sparkling water , grape juice require = 1/2 × 15/4 =

15/2 Quart of grape juice required for 15/4 quarts of sparkling water.

3)

in 1 we calculated that 18 Quart of Sparkling water need to mix with 9 quart grape juice that is 2 quart of Sparkling water need to mix with 1 quart of grape juice.

In other words 1 quart of grape juice + 2 quart of sparkling water is 3 quart of punch.

Quantity of Grape juice in 3 quart of punch = 1 quart

so quantity of grape juice in 1 quart of punch = 1/3 quart

And quantity of grape juice in 100 quart of punch = 100×(1/3) = 100/3 =

33 1/3

Quantity of sparkling water in 3 quart of punch = 2 quart

so quantity of sparkling water in 1 quart of punch = 2/3 quart

And quantity of sparkling water in 100 quart of punch = 100 ×2/3 quart = 66 2/3

You might be interested in

What is square root of the product of the number z and itself<br>

dsp73

Answer:

$\large\boxed{z}$

Step-by-step explanation:

What is square root of the product of the number z and itself?

Break down into smaller parts

What is the product of the number z and itself?

Product = multiply

Write an equation multiplying z by itself

z * z

Bring back the full question: What is the square root of the product of the number z and itself?

Now we can just add a $\sqrt{}$ to the front of our equation to solve the problem.

$\sqrt{z * z}$

Simplify

z * z = $z^{2}$

$\sqrt{z^{2} }$

In this case, the square root cancels out the exponent ( $z^{2}$ ), so $\sqrt{z^{2} }$ can simplify to z.

Hope this helps :)

8 0

2 years ago

There are 360 people in my school. 15 take calculus, physics, and chemistry, and 15 don't take any of them. 180 take calculus. T

lesantik [10]

Answer:

150 students take physics.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that take calculus.

-The set B represents the students that take physics

-The set C represents the students that take chemistry.

-The set D represents the students that do not take any of them.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a is the number of students that take only calculus, $A \cap B$ is the number of students that take both calculus and physics, $A \cap C$ is the number of students that take both calculus and chemistry and $A \cap B \cap C$ is the number of students that take calculus, physics and chemistry.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following subsets:

$a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C), D$

There are 360 people in my school. This means that:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) + D = 360$

The problem states that:

15 take calculus, physics, and chemistry, so:

$A \cap B \cap C = 15$

15 don't take any of them, so:

$D = 15$

75 take both calculus and chemistry, so:

$A \cap C = 75$

75 take both physics and chemistry, so:

$B \cap C = 75$

30 take both physics and calculus, so:

$A \cap B = 30$

Solution:

The problem states that 180 take calculus. So

$a + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 180$

$a + 30 + 75 + 15 = 180$

$a = 180 - 120$

$a = 60$

Twice as many students take chemistry as take physics:

It means that: $C = 2B$

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$B = b + 75 + 30 + 15$

$B = b + 120$

-------------------------------

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$C = c + 75 + 75 + 15$

$C = c + 165$

----------------------------------

Our interest is the number of student that take physics. We have to find B. For this we need to find b. We can write c as a function o b, and then replacing it in the equations that sums all the subsets.

$C = 2B$

$c + 165 = 2(b+120)$

$c = 2b + 240 - 165$

$c = 2b + 75$

The equation that sums all the subsets is:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) + D = 360$

$60 + b + 2b + 75 + 30 + 75 + 15 + 15 = 360$

$3b + 270 = 360$

$3b = 90$

$b = \frac{90}{3}$

$b = 30$

30 students take only physics.

The number of student that take physics is:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$B = b + 75 + 30 + 15$

$B = 30 + 120$

$B = 150$

150 students take physics.

6 0

2 years ago

ABC is translated 6 units up and 3 units left to crest A’B’C’. If vertex A is at (-1,2) and vertex B is at (1, 5) then vertex A’

jekas [21]

The translation is

... (x, y) ⇒ (x -3, y +6) . . . . . 3 units left, 6 units up

Then

... A(-1, 2) ⇒ A'(-1-3, 2+6) = A'(-4, 8)

... B(1, 5) ⇒ B'(1 -3, 5 +6) = B'(-2, 11)

3 0

2 years ago

A storage tank is a right-circular cylinder 20 ft long and 8 ft in diameter with its axis horizontal. If 3 the tank is half full

Arada [10]

Answer:

Step-by-step explanation:

The step by step calculation is as shown in the attached file.

3 0

2 years ago

Read 2 more answers

What are the roots of the quadratic function f(b)=b^2-75

Ivahew [28]

Set f(b) = b^2 - 75 = to 0 and solve for b:

b^2 = 75
b^2 = 25(3)
b = plus or minus sqrt(25[3]) = plus or minus sqrt(25)*sqrt(3) = plus or minus 5 sqrt(3).

5 0

2 years ago