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pav-90 [236]
1 year ago
9

The students at Southern Junior High School are divided into four homerooms. Benjamin just moved into the school district and wi

ll be randomly assigned to one homeroom.
Which methods can be used to simulate this situation? Select three options..

Flip a coin 4 times, once for each homeroom, with heads up representing being assigned to the homeroom represented by that flip.
Draw a marble from a bag containing 5 white marbles, 5 black marbles, 5 red marbles, and 5 green marbles, with each color representing a different homeroom.

Use a random number generator with 1, 2, and 12 representing the first homeroom, 7, 9, and 10 representing the second homeroom, 3, 8, and 11 representing the third homeroom, and 4, 5, and 6 representing the fourth homeroom.

Roll a number cube with 1 representing the first homeroom, 2 representing the second homeroom, 3 representing the third homeroom, and any other outcome representing the fourth homeroom.

Spin a spinner with 8 congruent sections with 2 sections assigned to each homeroom.
will give 100 points for answer it'd better be correct though
Mathematics
1 answer:
levacccp [35]1 year ago
8 0

Answer:

Step-by-step explanation:

Roll a number cube with 1 representing the first homeroom, 2 representing the second homeroom, 3 representing the third homeroom, and any other outcome representing the fourth homeroom.

Flip a coin 4 times, once for each homeroom, with heads up representing being assigned to the homeroom represented by that flip.

Draw a marble from a bag containing 5 white marbles, 5 black marbles, 5 red marbles, and 5 green marbles, with each color representing a different homeroom.

Spin a spinner with 8 congruent sections with 2 sections assigned to each homeroom.

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3.18x16 =_____hundredths +_____hundredths=_____hundredths=____
kari74 [83]
3.18x16=50.88 hundredths
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1 year ago
Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uyly∫uzlz∫uxlxdxdzdy
motikmotik

Answer:

Hello your question is incomplete attached below is the complete question

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

Step-by-step explanation:

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

attached below is the detailed solution

4 0
1 year ago
what is the answer to this A cylinder has a base diameter of 8ft and a height of 17ft. What is its volume in cubic ft, to the ne
LekaFEV [45]

Answer:

855 cft

Step-by-step explanation:

(22/7)*4*4*17=855cft(rounded )

5 0
1 year ago
Marcello is constructing the perpendicular bisector of AB¯¯¯¯¯. He has already constructed arcs as shown.
Ratling [72]

Answer: "Use the straightedge to draw a line through points X and Y." is the right answer.


Step-by-step explanation:

To perpendicular bisector of line segment AB. There are following steps:

1) Draw arcs from points A and B on the both sides of AB.

2) Name the intersection points as X and Y.

3) Use the straightedge to draw a line through points X and Y.

4) Name the point as O

hence we have construct perpendicular bisector XY of AB which bisects at O.

3 0
2 years ago
On her first day in a hospital, Kiri receives u1 milligrams (mg) of a therapeutic drug. The amount of the drug Kiri receives inc
Valentin [98]

Answer:

a. 21 = u1 + 6·d

b. 29 = u1 + 10·d

c. d = 2, u1 = 9

Step-by-step explanation:

a. The given parameters are;

The amount of therapeutic drug Kiri receives on her first at the hospital = u1 milligrams

The amount of drug increase received by Kiri each day = d

The amount of drug Kiri received on the seventh day = 21 mg

The amount of drug she received on the eleventh day = 29 mg

Therefore, we have an arithmetic progression with the formula for the nth term given as follows;

aₙ = a₁ + (n - 1)·d

Where;

a₁ = u1

n = The number of terms

Therefore, for the 7th day, the amount of drugs she receives, which is 21 milligrams, is given as follows;

a₇ = u1 + (7 - 1)·d = u1 + 6·d = 21

The equation for the amount of drugs she receives in terms of u1 and d on the seventh day is given as follows;

21 = u1 + 6·d

b. For the eleventh day, the amount of drugs she receives, which is 29 milligrams, is given as follows;

a₁₁ = u1 + (11 - 1)·d = u1 + 10·d = 29

Therefore, the equation for the amount of drugs she receives in terms of u1 and d on the  eleventh day is given as follows;

29 = u1 + 10·d

c. Therefore, we have two equations which are given as follows;

21 = u1 + 6·d................(1)

29 = u1 + 10·d..............(2)

Subtracting equation (1) from equation (2) gives;

29 - 21 = (u1 + 10·d) - (u1 + 6·d)

8 = 4·d

d = 8/4 = 2

d = 2

From equation (1), we have;

21 = u1 + 6·d = u1 + 6×2 = u1 + 12

21 = u1 + 12

21 - 12 = u1

∴ u1 = 9

d = 2, u1 = 9.

4 0
1 year ago
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