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2 years ago

a bus is traveling at a velocity of 25 m/s straight south what effect will an acceleration of 4m/s2 north have on a bus

Mathematics

1 answer:

Vadim26 [7]2 years ago

3 0

Answer:

The acceleration will cause the bus to travel for 6.25secs

Step-by-step explanation:

For us to get the effect the acceleration will have on the bus, we need to calculate the time taken by the bus to travel.

Using the acceleration formula;

Acceleration = Velocity/Time

Given

Acceleration = 4m/s²

Velocity = 25m/s

Required

Time

From the formula;

Time = Velocity/acceleration

Time = 25/4

Time = 6.25secs

Hence the acceleration will cause the bus to travel for 6.25secs

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Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation?

Nady [450]

For this case we have the following polynomial:
$x ^ 2 = 12x - 15
$
The first thing to do is to place the variables on the same side of the equation.
We have then:
$x ^ 2 - 12x = -15
$
We complete the square by adding the term (b / 2) ^ 2 on both sides of the equation.
We have then:
$x ^ 2 - 12x + (-12/2) ^ 2 = -15 + (-12/2) ^ 2
$
Rewriting we have:
$x ^ 2 - 12x + (-6) ^ 2 = -15 + (-6) ^ 2

x ^ 2 - 12x + 36 = -15 + 36
 
(x-6) ^ 2 = 21$
$x-6 =+/- \sqrt{21}$
Therefore, the solutions are:
$x = 6 - \sqrt{21}$
$x = 6 + \sqrt{21}$
Answer:
the solution set of the equation is:
$x = 6 - \sqrt{21}$
$x = 6 + \sqrt{21}$

3 0

2 years ago

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During geometry class, students are told that ΔTSR ≅ ΔUSV. Marcus states that ΔTSR is mapped to ΔUSV by performing a rotation ab

Paha777 [63]

Answer: Both students are correct.

Explanation:

In rotation a shape is rotated about a fixed point and it does not affect its measurements. it only changes its position.

Now, When Marcus rotated the $\triangle TSR$ about point S then this process did not affect its shape and size this is why he got the $\triangle USV$ which is congruent to the $\triangle TSR$ .

In reflection, when a shape reflected across a line then its all points get reflected across this line. But it also does not affect the measurement of the shape.

So, when Sam mapped $\triangle USV$ by the reflection of $\triangle TSR$ then the measurement of the $\triangle USV$ did not change. And, he also got the congruent triangle.

Thus, we can say that, Both Marcus and Sam are right.

7 1

2 years ago

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Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)

UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600$

Therefore, the probability is

$P=\frac{12117600}{53524680}\\\\P=0.226$

b) We calculate the probability that are at least 2 red balls.

We calculate the probability withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations: for 1 red balls

$C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848$

Therefore, the probability is

$P_1=\frac{16138848}{53524680}\\\\P_1=0.3$

We calculate the number of favorable combinations: for none red balls

$C_7^{34}=5379616$

Therefore, the probability is

$P_0=\frac{5379616}{53524680}\\\\P_0=0.1$

Therefore, the the probability that are at least 2 red balls is

$P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6$

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056$

Therefore, the probability is

$P=\frac{44056}{53524680}\\\\P=0.0008$

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

$P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\$

Let Y, event that exactly 3 blue balls selected.

$P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\$

We have

$P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12$

Therefore, we get

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74$

8 0

2 years ago

Each state imposes its own excise tax on gasoline. Suppose, for example, that the state of Massachusetts imposes a state gasolin

vovangra [49]

Complete question :

Each state imposes its own excise tax on gasoline. Suppose, for example, that the state of Massachusetts imposes a state gasoline tax of $0.26 per gallon. Suppose further that an average of 1,022,000 gallons of gasoline per day were sold in Massachusetts in 2010. The average revenue from gasoline tax in 2010 is approximately?

Answer:

$265,720

Step-by-step explanation:

Given that:

State gasoline tax = $0.26 per gallon

Average number of gasoline sold per day = 1,022,000 gallons

. From the availabke information given :

Revenue generated = gasoline tax per gallon multiplied by the average number of gallons sold

= $0.26 * 1,022,000

= $265,720

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2 years ago

Solve y = 7x-3w for x

lorasvet [3.4K]

Y=7x-3w
y+3w=7x
y+3w/7=x

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2 years ago

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