A furniture manufacturer produces chairs and sofas. Each chair requires 10 yards of fabric, and each sofa requires 20 yards of f
2 answers:
Given:
Fabric required for each chair = 10 yards
Fabric required for each sofa = 20 yards.
Total available fabric = 300 yards.
The number of sofas must be at least twice the number of chairs.
Profit on each chair = $50
Profit on each sofa = $80.
To find:
The function that represents the manufacturer's profit, P.
Solution:
Let P represents the manufacturer's profit, x represent the number of chairs and y represent the number of sofas.
Profit on 1 chair = $50
Profit on x chairs = $50x
Profit on 1 sofa = $80
Profit on y sofas = $80y
Total profit = Profit on x chairs + Profit on y sofas
Therefore, the required profit function is .
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Answer:
The greatest prime factor of k is 11.
Step-by-step explanation:
∵ LCM( 2, 15) = 30,
Thus, the even multiple of 15 must be multiple of 30,
That is, the even multiple of 15 between 295 and 615 are
300, 330, 360,..........600
Which is an AP,
Having first term, a = 300,
Common difference, d = 30,
If n be the number terms,
Last term =
Hence, the sum of the all even multiple of 15 from 295 to 615,
According to the question,
⇒ k = 11 × 450 = 11 × 5 × 5 × 3 × 3 × 2
Hence, the greatest prime factor of k is 11.