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aliina [53]
1 year ago
8

Eighteen individuals who use a particular form of social media were assigned a new user interface to use when logging into their

accounts. after using the new user interface for a week, each individual was asked to rate how easy or hard the new user interface was to use on a scale from 1 (extremely easy) to 9 (extremely hard). which of the following correctly identifies why this is not a well designed experiment?
A. There was a lack of control because not all individuals in the study used login passwords of the same length

B. The individuals may not have been randomly selected

C. There was not enough replication because the individuals used the new user interface for only one week.

D. there was a lack of control because not all individuals in the study use social media

E. the study was not comparative- only one treatment was used.
Mathematics
2 answers:
lianna [129]1 year ago
5 0

Answer:

Answer E . The study was not comparative—only one treatment was used.

Step-by-step explanation:

Well-designed experiments should involve comparisons of at least two treatment groups, one of which could be a control group.

Lisa [10]1 year ago
3 0

Answer:

E: The study was not comparative—only one treatment was used.

Step-by-step explanation:

Well-designed experiments should involve comparisons of at least two treatment groups, one of which could be a control group.

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A prticular type of tennis racket comes in a midsize versionand an oversize version. sixty percent of all customers at acertain
svetlana [45]

Answer:

a) P(x≥6)=0.633

b) P(4≤x≤8)=0.8989 (one standard deviation from the mean).

c) P(x≤7)=0.8328

Step-by-step explanation:

a) We can model this a binomial experiment. The probability of success p is the proportion of customers that prefer the oversize version (p=0.60).

The number of trials is n=10, as they select 10 randomly customers.

We have to calculate the probability that at least 6 out of 10 prefer the oversize version.

This can be calculated using the binomial expression:

P(x\geq6)=\sum_{k=6}^{10}P(k)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\geq6)=0.2508+0.215+0.1209+0.0403+0.006=0.633

b) We first have to calculate the standard deviation from the mean of the binomial distribution. This is expressed as:

\sigma=\sqrt{np(1-p)}=\sqrt{10*0.6*0.4}=\sqrt{2.4}=1.55

The mean of this distribution is:

\mu=np=10*0.6=6

As this is a discrete distribution, we have to use integer values for the random variable. We will approximate both values for the bound of the interval.

LL=\mu-\sigma=6-1.55=4.45\approx4\\\\UL=\mu+\sigma=6+1.55=7.55\approx8

The probability of having between 4 and 8 customers choosing the oversize version is:

P(4\leq x\leq 8)=\sum_{k=4}^8P(k)=P(4)+P(5)+P(6)+P(7)+P(8)\\\\\\P(x=4) = \binom{10}{4} p^{4}q^{6}=210*0.1296*0.0041=0.1115\\\\P(x=5) = \binom{10}{5} p^{5}q^{5}=252*0.0778*0.0102=0.2007\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\\\P(4\leq x\leq 8)=0.1115+0.2007+0.2508+0.215+0.1209=0.8989

c. The probability that all of the next ten customers who want this racket can get the version they want from current stock means that at most 7 customers pick the oversize version.

Then, we have to calculate P(x≤7). We will, for simplicity, calculate this probability substracting P(x>7) from 1.

P(x\leq7)=1-\sum_{k=8}^{10}P(k)=1-(P(8)+P(9)+P(10))\\\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\leq 7)=1-(0.1209+0.0403+0.006)=1-0.1672=0.8328

7 0
1 year ago
A businessman bought a car dealership that is incurring a loss of $500,000 a year. He decided to strategize in order to turn the
UkoKoshka [18]
The correct answer would be choice A: 1.

When 3 coins are flipped, there are 8 possible outcomes.

0 Tails = 1 ways
1 Tails = 3 ways
2 Tails = 3 ways
3 Tails = 1 ways

If you add up all the different tails, you could get 12 tails. Divide 12 by 8 and you have 1.5 which is the average number of tails you could expect to get by flipping 3 coins.
4 0
1 year ago
3 x 1/6 in simplest form
Travka [436]
Im not sure but i thing its 0.5 or 1/2
cause if you take (3/1)*(1/6) that's what you will get
also you had to make 3 as a fraction so you would put the denominator as 1 so if you divide 1 and 3 you would still get the whole number as 3
6 0
2 years ago
Read 2 more answers
On a coordinate plane, parallelogram P Q R S is shown. Point P is at (negative 2, 5), point Q is at (2, 1), point R is at (1, ne
Oksanka [162]

Answer:

The perimeter is (8\sqrt{2}+2\sqrt{10})\ units

Step-by-step explanation:

we know that

A parallelogram is a quadrilateral where both pairs of opposite sides are parallel and equal

so

In this problem

PS=QR ----> equation A

SR=PQ ----> equation B

The perimeter of parallelogram PQRS is

P=PQ+QR+SR+PS ----> equation C

substitute equation A and equation B in equation C

P=2SR+2QR

we have

QR=\sqrt{10}\ units

SR=4\sqrt{2}\ units

substitute in the formula of perimeter

P=2(4\sqrt{2})+2(\sqrt{10})

P=(8\sqrt{2}+2\sqrt{10})\ units

7 0
1 year ago
Read 2 more answers
The scores of eighth-grade students in a math test are normally distributed with a mean of 57.5 and a standard deviation of 6.5.
Anna11 [10]
Approximately 68% of a normal distribution lies within one standard deviation of the mean, so this corresponds to students with scores between (57.5 - 6.5, 57.5 + 6.5) = (51, 64)
8 0
2 years ago
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