Answer:
Step-by-step explanation:
Hello, please consider the following.
A. (x minus y)(y minus x)
This is not a difference of squares.
B. (6 minus y)(6 minus y)
This is not a difference of squares.
C. (3 + x z)(negative 3 + x z)
This is a difference of squares.
D. (y squared minus x y)(y squared + x y)
This is a difference of squares.
E. (64 y squared + x squared)(negative x squared + 64 y squared)
This is a difference of squares.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Answer:
jump discontinuity at x = 0; point discontinuities at x = –2 and x = 8
Step-by-step explanation:
From the graph we can see that there is a whole in the graph at x=-2.
This is referred to as a point discontinuity.
Similarly, there is point discontinuity at x=8.
We can see that both one sided limits at these points are equal but the function is not defined at these points.
At x=0, there is a jump discontinuity. Both one-sided limits exist but are not equal.
<span>m∠SYD = </span>106.02°
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Answer:
- hexahedron: triangle or quadrilateral or pentagon
- icosahedron: quadrilateral or pentagon
Step-by-step explanation:
<u>Hexahedron</u>
A hexahedron has 6 faces. A <em>regular</em> hexahedron is a cube. 3 square faces meet at each vertex.
If the hexahedron is not regular, depending on how those faces are arranged, a slice near a vertex may intersect 3, 4, or 5 faces. The first attachment shows 3- and 4-edges meeting at a vertex. If those two vertices were merged, then there would be 5 edges meeting at the vertex of the resulting pentagonal pyramid.
A slice near a vertex may create a triangle, quadrilateral, or pentagon.
<u>Icosahedron</u>
An icosahedron has 20 faces. The faces of a <em>regular</em> icosahedron are all equilateral triangles. 5 triangles meet at each vertex.
If the icosahedron is not regular, depending on how the faces are arranged, a slice near the vertex may intersect from 3 to 19 faces.
A slice near a vertex may create a polygon of 3 to 19 sides..
Let the distance be d
Using pythagorean theorem,
d ≈ 119
The player ran for
119 meters
