<span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4)
= </span><span>8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6 + 4r^5s^4
= </span>8r^6s^3 – 9r^5s^4 + 4r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6
= 8r^6s^3 – 5r^5s^4 + r^4s^5 + 5r^3s^6
Hope it helps
No, Leo's answer is not a product of prime polynomials because x2 – 1 can be factored. This is a difference of squares. He should continue factoring to get
(x – 1)(x + 1)(3x + 5).
8m(4+7p). (The greatest common factor is 8.).
The completely factored form of p^4-16 is:

Step-by-step explanation:
We have to factorize the given expression to get the final result
Given

p^2-4 can further be factored again
![=(p^2+4)[(p)^2-(2)^2]\\=(p^2+4)(p+2)(p-2)](https://tex.z-dn.net/?f=%3D%28p%5E2%2B4%29%5B%28p%29%5E2-%282%29%5E2%5D%5C%5C%3D%28p%5E2%2B4%29%28p%2B2%29%28p-2%29)
The completely factored form of p^4-16 is:

Keywords: Factorization
Learn more about factorization at:
#LearnwithBrainly
Answer:
11
Step-by-step explanation:
4=1
14=2
24=3
34=4
40=5
41=6
42=7
43=8
44=9
45=10
46=11
You will encounter 11 4s.