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1 year ago

How 0x86 processor store 0x12345678 in memory

Computers and Technology

1 answer:

snow_tiger [21]1 year ago

4 0

Answer:

The correct answer to this question is option a) 87, 65, 43, 21.

Explanation:

x86 is an Intel CPU construction that originated with the 16-bit 8086 processor.

The expression "x86" is used commonly to refer to any 32-bit processor compatible with the x86 instruction set.

The x86 architecture has a number of new features while staying almost entirely backward-compatible, which is a noteworthy achievement. That is why sequence 87, 65, 43, 21.

The vast margin of personal computers has x86 CPUs.

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Read 2 more answers

A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen

Nina [5.8K]

Answer:

C3H8

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of alkane = 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature (Kelvin) = Temperature (celsius) + 273

Temperature (celsius) = 28°C

Temperature (Kelvin) = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

Therefore, 741 mmHg = 741/760 = 0.975atm

Step 3:

Determination of the number of mole of the alkane..

The number of mole of the alkane can be obtained by using the ideal gas equation. This is illustrated below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 mole

Step 4:

Determination of the molar mass of the alkane.

Mass of alkane = 1.17g

Number of mole of the alkane = 0.0266mole

Molar Mass of the alkane =?

Number of mole = Mass/Molar Mass

Molar Mass = Mass/number of mole

Molar Mass of the alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determination of the molecular formula of the alkane.

This is illustrated below:

The general formula for the alkane is CnH2n+2

To obtain the molecular formula for the alkane we shall assume n = 1, 2, 3 or more till we arrive at molar Mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

We can see that when n is 3, the molar mass is 44g/mol.

Therefore, the molecular formula for the alkane is C3H8.

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Vikki [24]

Answer:

C++ code is given below

Explanation:

#include<iostream>

#include <cstring>

using namespace std;

int housekeeping(string EOFNAME);

int mainLoop(string name,string EOFNAME);

int finish();

void main()

{

string name;

string EOFNAME = "ZZZZ";

cout << "enter the name" << endl;

cin >> name;

if (name != EOFNAME)

{

housekeeping(EOFNAME);

}

if (name != EOFNAME)

{

mainLoop(name , EOFNAME);

}

if (name != EOFNAME)

{

finish();

}

system("pause");

}

int housekeeping(string EOFNAME)

{

cout << "enter first name " << EOFNAME << " to quit " << endl;

return 0;

}

int mainLoop(string name, string EOFNAME)

{

int hours;

int rate,gross;

int DEDUCTION = 45;

int net;

cout << "enter hours worked for " << name << endl;

cin >> hours;

cout << "enter hourly rate for " << name << endl;

cin >> rate;

gross = hours*rate;

net = gross - DEDUCTION;

if (net > 0)

{

cout << "net pay for " << name << " is " << net << endl;

}

else

{

cout << "dedections not covered.net is 0.";

}

cout << "enter next name or " << EOFNAME << " to quit" << endl;

cin >> name;

return 0;

}

int finish()

{

cout << "end of job"<<endl;

return 0;

}

3 0

2 years ago

How 0x86 processor store 0x12345678 in memory ​

How 0x86 processor store 0x12345678 in memory