Triangle J K L is shown. Lines are drawn from each point to the opposite side and intersect at point P. Line segments J O, K M,
2 answers:
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Answer:
Therefore the maximum error in the surface area of the sphere is 22.27 cm².
Therefore the relative error is 0.014 (approx).
Step-by-step explanation:
Given that, The circumference of a sphere was 70 cm with the possible error 0.5 cm.
The circumference of the sphere is C
∴C
Differentiating with respect to r
[ relative error = dC= 0.5]
The surface area of the sphere is S=
∴S=
Differentiating with respect to r
dS will be maximum when dr is maximum.
Putting the value of r and dr
[ ∵ C= 70 ]
⇒dS= 22.27 (approx)
Therefore the maximum error in the surface area is 22.27 cm².
Relative error
=0.014 (approx)
Therefore the relative error is 0.014 (approx).
Answer:
a) Cost
b) Sales income
c) Table of values
d) Attached
e) Breakeven point = 12.5 sheets
f) Profit at 550 sheets = $1,950
Step-by-step explanation:
a) We have a fixed cost for the image, at $50.
We also have a variable cost of $16 a sheet.
The purchased quantity is 500 sheets.
Then, the cost function is:
b) The price for each sheet is $20, so the income from sales are:
c) Table of values
d) Attached
e) The minimum number of sheets the group must sell so they don't lose any money is the breakeven point (BEP) and can be calculated making the income sales equal to the cost:
f) This profit can be calculated as the difference between the sales income and the cost:
