Question

Triangle J K L is shown. Lines are drawn from each point to the opposite side and intersect at point P. Line segments J O, K M, and L N are created.
In the diagram, which must be true for point P to be the centroid of the triangle?

LN ⊥ JK, JO ⊥ LK, and JL ⊥ MK.
JL = LK = KJ
JM = ML, LO = OK, and KN = NJ.
LN is a perpendicular bisector of JK, JO is a perpendicular bisector of LK, and MK is a perpendicular bisector of JL.

Answer 1

Answer:

JM = ML, LO = OK, and KN = NJ

Step-by-step explanation:

This makes the most sense.

Answer 2

Answer:

C

Step-by-step explanation:

JM = ML, LO = OK, and KN = NJ