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1 year ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Mathematics

2 answers:

Contact [7]1 year ago

8 0

Answer: EDMENTUM AND PLATO

First Blank: $625

Second Blank: 20

Third Blanks: ( 0, 20 )

Step-by-step explanation:

lord [1]1 year ago

3 0

Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph

To Find : Maximum profit , breakeven point , profit interval

Solution:

The maximum profit the florist will earn from selling celebration bouquets is $ 675

peak of y from Graph

The florist will break-even after Selling 20 one-dollar decreases.

at breakeven

Break even is the point where the profit p(x) becomes 0

The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).

after 20 , P(x) is - ve

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Jillian is selling boxes of cookies to raise money for her basketball team. The 10 oz. box costs $3.50, while the 16 oz. box cos

cluponka [151]

<span>we have to solve simultaneous equations.

x = 10 oz. boxes

y = 16 oz. boxes

simultaneous equations

x + y = 24 ---1)

3.50x + 5.00y = 97.50 ----2)

to solve for x we need to eliminate y, therefore we have to multiply 1st equation by 5

5x + 5y = 120 --3)

subtract 3) - 2)

5x - 3.50x = 120 - 97.50

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6 0

2 years ago

Read 2 more answers

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Serjik [45]

Step-by-step explanation:

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Emento-ang mga Elemento na ma tag puan sa parabulang kwento at banghay ng kwento.

Nilalaman-ang nilalaman ng parabula ay tungkol sa isang katiwala na nag lulustay ng ari-arian sa kanyang amo.

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2 years ago

A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random

Harlamova29_29 [7]

Answer with explanation:

Given : Sample mean = $\overline{x}=\text{48.47 pounds}$

Standard deviation : $\sigma=\text{ 3.1 pounds.}$

Sample size : n = 36

Claim : $\mu\neq50$

∴ $H_0:\mu=50$

$H_1:\mu\neq50$

Since the alternative hypothesis is two tail , then the test is two tail test.

By using a z statistic and a 0.05 level of significance. Reject $H_0$ if z < -1.960 or is z> 1.960.

Then , the test static for population mean is given by :-

$z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

$z=\dfrac{48.47-50}{\dfrac{3.1}{\sqrt{36}}}\approx-2.96$

We reject $H_0$ since $-2.96\leq -1.96$ . We have statistically significant evidence at $\alpha=0.05$ to show that the mean amount of garbage per bin is not different from 50.

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2 years ago

At Brighton Middle School, Mr. Yule asked 50 randomly selected students from each grade level about their favorite subject, and

Ugo [173]

Answer:

Yes, he made a reasonable inference by saying about 25 percent of students choose the science.

Step-by-step explanation:

Given that

Number of students for survey = 50

Number of students who choose science = 12

Now

Percentage of student who choose science = $\frac{12}{50} x 100$

Percentage of student who choose science = $\frac{12*100}{50}$

Percentage of student who choose science = 24 %

Now as Mr. Yule said "about 25" percent of students choose the science it can be treated as reasonable approximation.

Now if the number of students in survey become 200, then we can expect 12 out of every 50 students would choose the science. So, in total 48 students would choose the science.

Now lets calculate the percentage of students who choose science.

Percentage of student who choose science = $\frac{48}{200} x 100$