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Ganezh [65]
2 years ago
4

Beverly has a bag of marbles that weighs 30 grams. She knows that each marble weighs 1.5 grams and the bag weighs 1.5 grams. Whi

ch equation could she use to determine how many marbles are in the bag? Select all that apply. (1.5)x + 1.5 = 30 30 – x = 2(1.5) (1.5)(30) = 1.5x 1.5 + x = 30 1.5x = 30 – 1.5
Mathematics
2 answers:
alexdok [17]2 years ago
8 0

a & c


or (1.5)x + 1.5 = 30 and 1.5x = 30 – 1.5


hope this helps :)

denpristay [2]2 years ago
3 0

Hey :D

The other guy means A & E!!

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Sidana [21]

Answer:

Frozen\ Soup = 7550mL

Step-by-step explanation:

Given

Soup = 9,350mL

Packed = 1.8L

Required

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This is calculated as thus:

Frozen\ Soup = 9,350mL - 1.8L

Convert 1.8L to mL

Frozen\ Soup = 9,350mL - 1.8 * 1000mL

Frozen\ Soup = 9,350mL - 1,800mL

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7 0
2 years ago
According to the Rational Root Theorem, which is a factor of the polynomial f(x) = 3x3 – 5x2 – 12x + 20?
Harlamova29_29 [7]

3x^3 – 5x^2 – 12x + 20

= (3x^3 – 5x^2) – (12x - 20)

= x^2(3x - 5) - 4(3x - 5)

= (3x - 5)(x^2 - 4)

= (3x - 5)(x + 2)(x - 2)


Factors: (3x - 5), (x + 2), and (x - 2)


Answer:

D.) 3x – 5

8 0
2 years ago
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What is the expected price of a calculator in the year 2000 if it costs $19.12 in 2015? You can use the chart below for a refere
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2 years ago
The number of messages that arrive at a Web site is a Poisson distributed random variable with a mean of 6 messages per hour. Ro
QveST [7]

Answer:

a) There is a 16.0623% probability that 5 messages are received in 1 hour.

b) There is a 11.5880% probability that 10 messages are received in 1.5 hours.

c) There is a 22.4042% probability that 2 messages are received in 0.5 hours.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

In this problem, we have a mean of 6 messages per hour.

(a) What is the probability that 5 messages are received in 1 hour?

Find the value of P when x = 5 and \mu = 6

So

P(X = 5) = \frac{e^{-6}*(6)^{5}}{(5)!} = 0.160623

There is a 16.0623% probability that 5 messages are received in 1 hour.

(b) What is the probability that 10 messages are received in 1.5 hours?

The mean is 6 messages in one hour.

For 1.5 hours, the mean is 6*1.5 = 9 messages.

So

We have to find the value of P when x = 10 and \mu = 9.

P(X = 10) = \frac{e^{-9}*(9)^{10}}{(10)!} = 0.115880

There is a 11.5880% probability that 10 messages are received in 1.5 hours.

(c) What is the probability that less than 2 messages are received in 1/2 hour?

The mean is 6 messages in one hour.

For 0.5 hours, the mean is 6*0.5 = 3 messages.

So

We have to find the value of P when x = 2 and \mu = 3.

P(X = 10) = \frac{e^{-3}*(3)^{2}}{(2)!} = 0.224042

There is a 22.4042% probability that 2 messages are received in 0.5 hours.

6 0
2 years ago
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