<h3>
Answer:</h3>
equations
solution
<h3>
Step-by-step explanation:</h3>
Let "a" and "c" represent the numbers of adult and children's tickets sold, respectively. The problem statement tells us two relationships between these values:
... 20a +10c = 15000 . . . . . . total revenue from ticket sales
... c = 3a . . . . . . . . . . . . . . . . relationship between numbers of tickets sold
Using the expression for c, we can substitute into the first equation to get ...
... 20a +10(3a) = 15000
... 50a = 15000
... a = 15000/50 = 300 . . . . . adult tickets sold
... c = 3·300 = 900 . . . . . children's tickets sold
Answer: I'm pretty sure it would be -7º Celcius for it to be cancelled. Hope it helped!
612/6=102
check: 6x102=612
Hope this helped! :))
Answer:
1 ± √47
Step-by-step explanation:
Combine like terms in 2x^2 +3 x-7 =x^2 +5x +39:
2x^2 - x^2 = x^2 (first term);
3x - 5x = -2x (second term);
-7 - 39 = -46 (third term)
Then we have, all on the left side, x^2 - 2x - 46, which is a quadratic equation. Here the coefficients are a = 1, b = -2 and c = -46.
Then the discriminant, b^2 - 4ac, is:
(-2)^2 - 4(1)(-46) = 4 + 184.
The roots are:
-(-2) ±√188 2 ± √4√47
------------------- = -------------------
2 2
= 1 ± √47 (last of the answer choices)
=
x = ------------------
Answer:
The wagon can hold 32 newspapers
Step-by-step explanation:
