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ra1l [238]
2 years ago
12

In this challenge, your input will be three lines, each containing a string. The first line will be stored in the variable s1, t

he second in s2, and the third in s3. Define a variable called joined_with_commas that holds a string with the contents of s1, followed by a comma, followed by s2, followed by a comma, followed by s3.
Computers and Technology
1 answer:
Natali5045456 [20]2 years ago
3 0

Answer:

Answered below.

Explanation:

This challenge is solved using Python programming language.

#First getting the inputs and storing them in #variables s1, s2, s3

s1 = input ("Enter first string: ")

s2 = input("Enter second string: ")

s3 = input ("Enter third string: ")

#Then joining them with commas to make one #string.

joined_with_commas = "$s1 , $s2 , $s3"

print (joined_with_commas)

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In this exercise you will debug the code which has been provided in the starter file. The code is intended to take two strings,
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Answer:

Here is the corrected program:

import java.util.Scanner; //to accept input from user

public class 02_14_Activity_one { //class name

    public static void main(String[] args) { //start of main method

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  System.out.println("Enter first string"); //prompts user to enter first string

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          int n = scan.nextInt(); //reads value of integer n from user

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Explanation:

The errors were:

1.

Scanner scan = Scanner(System.in);

Here new keyword is missing to create object scan of Scanner class.

Corrected statement:

 Scanner scan = new Scanner(System.in);

2.

String s1 = nextLine();  

Here object scan is missing to call nextLine() method of class Scanner

Corrected statement:

String s1 = scan.nextLine();

3.

String s2 = Scanner.nextLine();

Here class is used instead of its object scan to access the method nextLine

Corrected statement:

String s2 = scan.nextLine();

4.

String n = scan.nextLine();

Here n is of type String but n is a whole number so it should be of type int. Also the method nextInt will be used to scan and accept an integer value

Corrected statement:

int n = scan.nextInt();

5.

System.out.println(s1.substring(1,n-1) + s2.substring(s1.length()-n));

This statement is also not correct

Corrected statement:

System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));

This works as follows:

s1.substring(0,n) uses substring method to return a new string that is a substring of this s1. The substring begins at the 0th index of s1 and extends to the character at index n.

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The screenshot of program along with its output is attached.

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Answer:

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