I have a variable and set it equal to 5. 1 then send it as an argument to a function that adds 5 to the variable passed in. Outs
1 answer:
Answer:
D. 5
Explanation:
If the variables original value was 5 then the value that will be printed is 5. This is because the variable is being passed as a parameter into the function and 5 is being added to the parameter value, not the actual global variable outside. Therefore, in order for the adjusted value to be printed then that new value that is returned by the function needs to be saved in a new variable. This can be seen in the example code below.
You might be interested in
Answer:
Explanation:
The following code is written in Java and creates the overloaded methods as requested. It has been tested and is working without bugs. The test cases are shown in the first red square within the main method and the output results are shown in the bottom red square...
class Auction {
public static void main(String[] args) {
bid(10);
bid(10.00);
bid("10 dollars");
bid("$10");
bid("150 bills");
}
public static void bid(int bid) {
if(bid >= 10) {
System.out.println("Bid Accepted");
} else {
System.out.println("Bid not high enough");
}
}
public static void bid(double bid) {
if(bid >= 10) {
System.out.println("Bid Accepted");
} else {
System.out.println("Bid not high enough");
}
}
public static void bid(String bid) {
if (bid.charAt(0) == '$') {
if (Integer.parseInt(bid.substring(1, bid.length())) > 0) {
System.out.println("Bid Accepted");
return;
} else {
System.out.println("Bid not in correct Format");
return;
}
}
int dollarStartingPoint = 0;
for (int x = 0; x < bid.length(); x++) {
if (bid.charAt(x) == 'd') {
if (bid.substring(x, x + 7).equals("dollars")) {
dollarStartingPoint = x;
} else {
break;
}
}
}
if (dollarStartingPoint > 1) {
if (Integer.parseInt(bid.substring(0, dollarStartingPoint-1)) > 0) {
System.out.println("Bid Accepted");
return;
} else {
System.out.println("Bid not in correct format");
return;
}
} else {
System.out.println("Bid not in correct format");
return;
}
}
}
