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postnew [5]
1 year ago
11

A line graph titled Unemployment Percentages and Levels of Education where the x-axis shows dates from November 2007 to November

2010 and the y-axis shows the percentage unemployed. No High School diploma starts at 7.5 percent in November 2007, rises steadily to 15 percent in November 2009, and stays at 15 percent to November 2010. High School diploma starts at 4.8 percent, rises steadily to 10.5 percent in November 2009, and falls to 9.5 percent in November 2010. Some college starts at 4 percent in November 2007, rises to 9 percent in November 2009, and falls to 8 percent in November 2010. Bachelor's degree or higher starts at 2 percent, rises to 5 percent in November 2009, and slowly falls to 4.9 percent in November 2010.
Based on the above graph, what was the percentage of difference between someone without a high school diploma and someone who has completed some college in November 2009?

A.

4%

B.

5%

C.

7%

D.

10%

can yall please answer my question pls
Computers and Technology
1 answer:
Svetradugi [14.3K]1 year ago
8 0

Answer:

D

Explanation:

the answer is D because

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A blood bank maintains two tables - DONOR, with information about people who are willing to donate blood and ACCEPTOR, with info
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Answer:

The sql query is given below.

Since we need to count of males and females for a particular blood group, we put xxx for the blood group.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors,

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FROM DONOR

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Explanation:

The clauses in the query are as follows.

1. SELECT: all the columns required in the output are put in this clause.

2. FROM JOIN ON: the table(s) from which the above columns are taken are put in this clause.

3. WHERE: any condition required to filter the output is put in this clause.

The query is explained below.

1. Find the number of male donors. Number of anything can be found using COUNT() function. A query is required since gender is included in deciding the type of donor.

2. The query is defined to find number of male donors as follows.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "M%"; )

3. In the previous query, LIKE operator is used since it is not defined what value is stored for male donors.

4. Similarly, the query to find the number of female donors is formed.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "F%"; )

5. Next, the final query is formed as follows.

SELECT: both COUNT() functions will come here.

FROM: table name

WHERE: specific blood group will be put here

GROUP BY: this clause is optional and is not used in this query.

HAVING: this clause is optional and is not used in this query.

6. The query after putting all clauses is shown below.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%"),

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%")

FROM DONOR

WHERE BG = xxx;

7. Alias is used in the above query for each column to get the final query.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors, COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

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