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2 years ago

How can rows be added to a table? Check all that apply

2 answers:

6 0

<h2><em>1) By drawing a row in the table using the draw option. </em></h2><h2><em> </em></h2><h2><em>2) By using the insert option under the Table Tools tab. </em></h2><h2><em> </em></h2><h2><em>3) By designing the table with an added row using the Design tab.</em></h2><h2><em></em></h2><h2><em>HOPE IT HELPS (◕‿◕✿)</em></h2>

creativ13 [48]2 years ago

5 0

Answer:

b and e

It's b (by using the Insert option under the Table Tools tab) and e (by clicking the plus sign that appears on the left side of the table)

Explanation:

I just did this on edgenuity, hope this helps! :)

Guest

1 year ago

It’s this oneeeee

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Rideshare companies like Uber or Lyft track the x,y coordinates of drivers and customers on a map. If a customer requests a ride

TiliK225 [7]

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

public static void main (String[]args){

Scanner input = new Scanner(System.in);

double user[] = new double[2]; double dr1[] = new double[2];

double dr2[] = new double[2]; double dr3[] = new double[2];

System.out.print("Enter user coordinates: ");

for(int i =0;i<2;i++){ user[i] = input.nextDouble(); }

System.out.print("Enter driver 1 coordinates: ");

for(int i =0;i<2;i++){ dr1[i] = input.nextDouble(); }

System.out.print("Enter driver 2 coordinates: ");

for(int i =0;i<2;i++){ dr2[i] = input.nextDouble(); }

System.out.print("Enter driver 3 coordinates: ");

for(int i =0;i<2;i++){ dr3[i] = input.nextDouble(); }

double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);

double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);

double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);

System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");

System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");

System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");

}

Explanation:

The following array declarations are for the customer and the three drivers

<em> double user[] = new double[2]; double dr1[] = new double[2];</em>

<em> double dr2[] = new double[2]; double dr3[] = new double[2]; </em>

This prompts the user for the customer's coordinates

System.out.print("Enter user coordinates: ");

This gets the customer's coordinate

for(int i =0;i<2;i++){ user[i] = input.nextDouble(); }

This prompts the user for the driver 1 coordinates

System.out.print("Enter driver 1 coordinates: ");

This gets the driver 1's coordinate

for(int i =0;i<2;i++){ dr1[i] = input.nextDouble(); }

This prompts the user for the driver 2 coordinates

System.out.print("Enter driver 2 coordinates: ");

This gets the driver 2's coordinate

for(int i =0;i<2;i++){ dr2[i] = input.nextDouble(); }

This prompts the user for the driver 3 coordinates

System.out.print("Enter driver 3 coordinates: ");

This gets the driver 3's coordinate

for(int i =0;i<2;i++){ dr3[i] = input.nextDouble(); }

This calculates the distance between driver 1 and the customer

double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);

This calculates the distance between driver 2 and the customer

double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);

This calculates the distance between driver 3 and the customer

double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);

The following print statements print the estimated pickup time of each driver

<em> System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");</em>

<em> System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");</em>

<em> System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");</em>

7 0

2 years ago

You are given an array x of string elements along with an int variable n that contains the number of elements in the array. You

Slav-nsk [51]

Answer:

The code to this question can be given as:

Code:

int i,j,count_previous=0,count_next=0; //define variable

for (j=0; j<n; j++) //loop for array

{

if (x[0]==x[j]) //check condition

{

count_previous++; //increment value by 1.

}

for (i=0; i<n; i++) //loop

{

for (j=0; j<n; j++)

{

if (x[i]==x[j]) //check condition

{

count_next++; //increment value by 1.

}

if (count_previous>count_next) //check condition

{

mode=x[i-1];

}

else

{

mode=x[i];

count_previous=count_next; //change value.

count_next= 0 ; //assign value.

}

Explanation:

In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.

8 0

2 years ago

Which set of variables will make code easier to understand?

Alecsey [184]

Answer:

sum, price, count

Explanation:

Programmers should use significant names for the variables.

Not only it makes it easier for them to remember what kind of information is stored in each variable, but it also makes life simpler for anyone who would read the code later.

Names like sum, price and count are significant names ( assuming they actually hold this kind of data), and will make the re-reading of the program code much easier.

8 0

2 years ago

____ twisted pair is the least quality twisted pair wire that should be used in a data/voice application.

xxMikexx [17]

Answer:

Category 5 (Cat 5) twisted pair is the least quality twisted pair wire that should be used.

Explanation:

The reason is as follows:

Category 1 twisted pair is not suitable for transmitting data but comes in handy for telephone communications. Hence, it should not be used in a data/voice application.
Category 2 twisted pair is suitable for data transmission, however, it can only transmit at 4Mbps which is very slow. Hence, it should not be used in a data/voice application.
Category 3 twisted pair can transmit data with speed reaching 10Mbps which is slow for voice/data communication.
Category 4 twisted pair can transmit data with speed reaching 16Mbps and is used in token ring networks. It is slow for communicating in a voice/data application.
Category 5 twisted pair is the least qualified to be used in a voice/data application because it can transmit data at speeds that reach 100Mbps.

Hence, Cat 5 or Category 5 twisted pair is the least quality twisted pair that should be used in a data/voice application.

6 0

2 years ago

If you’d like to have multiple italicized words in your document, how would you change the font of each of these words?

Mariana [72]

You select the words and then format - italics

5 0

2 years ago

Read 2 more answers