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Aleks04 [339]
2 years ago
12

An attack in which the attacker attempts to impersonate the user by using his or her session token is known as:

Computers and Technology
1 answer:
svetoff [14.1K]2 years ago
5 0

Answer:

Session hijacking

Explanation:

Session hijacking : Session hijacking is an attack where a user session is taken over by an attacker. A session starts when you log into a service, for example your banking application, and ends when you log out.

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Give the logical function for the following: If cell B7 equals 12, check contents of cell B10. If cell B10 is 10, then the value
ASHA 777 [7]

Answer:

=IF( B7 = 12, ( IF( B10 = 10,"YES", "")), 7) and PRESS ENTER

Explanation:

the above logical if function checks the following

-IF cell B7 is 12, if true, check the value of cell B10, IF cell B10 contains 10 the function should produce YES as output to whatever cell selected, IF B10 is not 10 output of the function should be an empty string, IF B7 is not equal to 12 the the output of the function should be 7.

5 0
2 years ago
What output is produced by the following program segment? Why? (Recall that name.charAt(i) is the i-th character in the string,
vekshin1

Answer:

The output is:

R

M

N

Explanation:

The code snippet print the beginning letter of each word in the given name.

In the for loop snippet:

first the program check if startWord is true and it is true, then it print the value of the character at index 0. Then it check if value of character is empty. If it is empty, startWord is initialized to true else it is initialized to false.

The loop only print a character when the value of i are 0, 8 and 11 which are also the beginning character of a word.

8 0
2 years ago
Considering the following algorithm, which of the following requirements are satisfied?
Alisiya [41]

Answer:

b) Bounded Waiting

Explanation:

int currentThread = 1;

bool thread1Access = true;

bool thread2Access = true;

thread1 { thread2 {

While (true) {

                   While (true)

                                   {

                     while(thread2Access == true)

                                       {

                                      while(thread1Access == true)

                                       {

                                            If (currentThread == 2) {

                                              If (currentThread == 1)

                                                {        

                                                  thread1Access = false; thread2Access = false;

                                                  While (currentThread == 2);

                                                 While (currentThread == 1);

                                                  thread1Access = true; thread2Access = true;

} }

/* start of critical section */ /* start of critical section */

currentThread = 2 currentThread = 1

… ...

/* end of critical section */ /* end of critical section */

thread1Access = false; thread2Access = false;

… ...

} }

} }

} }

It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.

4 0
2 years ago
Tyler wants to upgrade his very old operating system to the latest mac or microsoft operating system, but he cannot seem to inst
nordsb [41]
Every program has minimum system requirement, so at least His CPU is not good, or the amount of his RAM is too short to run the new version of OS.
6 0
2 years ago
Multiply each element in origList with the corresponding value in offsetAmount. Print each product followed by a semicolon (no s
Pavlova-9 [17]

Answer:

Replace /* Your code goes here */  with

for(i =0; i<NUM_VALS; i++) {

    printf("%d", origList[i]*offsetAmount[i]);

printf(";");

}

Explanation:

The first line is an iteration statement iterates from 0 till the last element in origList and offsetAmount

for(i =0; i<NUM_VALS; i++) {

This line calculates and print the product of element in origList and its corresponding element in offsetAmount

    printf("%d", origList[i]*offsetAmount[i]);

This line prints a semicolon after the product has been calculated and printed

printf(";");

Iteration ends here

}

5 0
2 years ago
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