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2 years ago

An attack in which the attacker attempts to impersonate the user by using his or her session token is known as:

Computers and Technology

1 answer:

svetoff [14.1K]2 years ago

5 0

Answer:

Session hijacking

Explanation:

Session hijacking : Session hijacking is an attack where a user session is taken over by an attacker. A session starts when you log into a service, for example your banking application, and ends when you log out.

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Which of the following is NOT a method in which a macro can be run?

liubo4ka [24]

C....................

7 0

2 years ago

Assume there is a machine with the IP address 129.82.102.63 with netmask /23, and with a parent NW whose netmask is 255.255.224.

blagie [28]

Complete question is:

Assume there is a machine with the IP address 129.82.102.63 with netmask /23, and with a parent NW whose netmask is 255.255.224.0.

For each answer, do not include any spaces, give full IP addresses/netmasks where these are requested, give the "/" as part of the answer for slash notation.

a. What is the parent NW's netmask in dotted decimal notation?

b. What is the parent NW's netmask in slash notation?

c. What is the child NW's (subnet's) netmask in dotted decimal notation?

d. What is the child NW's (subnet's) netmask in slash notation?

e. How many bits are there for host # portion for the parent NW? (Another way to say the same thing is How many bits do we manage - on the parent NW?)

f. How many bits are there for NW# portion (within the parent address space) for the subnet?

g. How many bits are there for host # portion for the subnet?

h. How many addresses can we assign to machines/interfaces on this subnet?

Answer:

a. 255.255.224.0

b. /19

255.255 amounts to 16 bits being 1. .224 means 3 more bits are 1. So, in total 19 bits are 1. Hence, total network bits are 16 + 3 = 19.

c. 255.255.254.0

/23 means 8 + 8 + 7 that means

first 2 octets are 1s and 7 bits out of the 3rd octet are 1s. Hence, /23 means 255.255.254.0

d. /23

e. 13 bits are reserved for hosts

Parent network mask is /19, so total 32-19 = 13 bits

f. 19 bits are reserved for the network in the parent address.

g. 9 bits

Subnetwork's mask is /23, so total 32-23 = 9 bits for the host portion.

h. Since 9 bits are reserved for hosts, a total of 29 -2 = 510 machines can be assigned the IP addresses. Two addresses will be network and broadcast addresses for the subnet that can't be allocated to any device.

Explanation:

3 0

2 years ago

Suppose that the data mining task is to cluster points (with (x, y) representing location) into three clusters, where the points

solong [7]

Answer:

Explanation:

K- is the working procedure:

It takes n no. of predefined cluster as input and data points.

It also randomly initiate n centers of the clusters.

In this case the initial centers are given.

Steps you can follow

Step 1. Find distance of each data points from each centers.

Step 2. Assign each data point to the cluster with whose center is nearest to this data point.

Step 3. After assigning all data points calculate center of the cluster by taking mean of data points in cluster.

repeat above steps until the center in previous iteration and next iteration become same.

A1(4,8), A2(2, 4), A3(1, 7), B1(5, 4), B2(5,7), B3(6, 6), C1(3, 7), C2(7,8)

Centers are X1=A1, X2=B1, X3=C1

A1 will be assigned to cluster1, B1 will be assigned to cluster2 ,C1 will be assigned to cluster3.

Go through the attachment for the solution.

5 0

2 years ago

When you check to see how much RAM, or temporary storage you have available, you are checking your _____.

victus00 [196]

Answer: primary memory

5 0

2 years ago

Writing in Java, write a program that prompts the user to input an integer and then outputs both the individual digits of the nu

larisa [96]

Answer:

//Here is code in java.

import java.util.*;

class Main

{

public static void main (String[] args) throws java.lang.Exception

{

try{

int in;

//scanner class object to read the input

Scanner scr=new Scanner(System.in);

// variable to keep running total

int total=0;

System.out.println("please enter an Integer:");

// read the input first time

in=scr.nextInt();

System.out.print("individual digits of "+in+" is ");

if(in<0)

{

in=-(in);

}

//call the function to print the digits of number

print_dig(in);

System.out.println();

//calculate the sum of all digits

do{

int r=in%10;

total=total+r;

in=in/10;

}while(in>0);

//print the sum

System.out.println("total of digits is: "+total);

}catch(Exception ex){

return;}

}

//recursive function to print the digits of number

public static void print_dig(int num)

{

if(num==0)

return;

else

{

print_dig(num/10);

System.out.print(num%10+" ");

}

Explanation:

Read a number with the help of object of scanner class.if the input is negative

then make it positive number before calling the function print_dig().call

the recursive method print_dig() with parameter "num".It will extract the digits

of the number and print then in the order. Then in the main method, calculate

sum of all the digits of number.

Output:

please enter an Integer:

3456

individual digits of 3456 is 3 4 5 6

total of digits is: 18

please enter an Integer:

-2345

individual digits of -2345 is 2 3 4 5

total of digits is: 14

6 0

2 years ago