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2 years ago

14

if you had two proxy servers located in the same room, what use could you make of them? nothing create a hub sell one of the ser

vers set up a network neutral zone

Computers and Technology

2 answers:

Anit [1.1K]2 years ago

6 0

Create a free wifi service

Kamila [148]2 years ago

3 0

Answer:

create a hub

Explanation:

You might be interested in

Write code which takes a sentence as an input from the user and then prints the length of the first word in that sentence.

Afina-wow [57]

import java.util.Scanner;

public class U2_L3_Activity_Four {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

System.out.println("Enter a sentence.");

String sent = scan.nextLine();

int count = 0;

for (int i = 0; i < sent.length(); i++){

char c = sent.charAt(i);

if (c != ' '){

count++;

}

else{

break;

}

}

System.out.println("The first word is " + count +" letters long");

}

}

We check to see when the first space occurs in our string and we add one to our count variable for every letter before that. I hope this helps!

7 0

1 year ago

Arrays are described as immutable because they are two dimensional. are arranged sequentially. can be reordered. cannot be chang

Vlada [557]

Answer:

Arrays are described as immutable because they cannot be changed once they are defined. (D on Edge)

Explanation:

It's in the notes and I just took the test (2020)

6 0

2 years ago

When configuring a record type, an App Builder can configure the available value of a picklist field for the page layout. Which

Alla [95]

Answer:

Option (B) and (D) i.e., Type and Lead Source is the correct answer.

Explanation:

Because when the user configures the record type, Then, they can help that user to configure the value of the picklist fields for the page layout. So, The type and the lead source opportunity is available for the standard field that configure straightly in the type of record. That's why the following option is correct.

7 0

1 year ago

The initial value for a number field on a record is 1. A user updated the value of the number field to 10. This action invokes a

erik [133]

Answer: b. 11

Explanation:

//The initial value is 1

//let call the value as x

x = 1

//then the user updated the value to 10

//so now x is 10

x = 10

// and update the workflow to 11

//so now the value of x is 11

x = 11

even if the programmer print x, so the output will be 11

3 0

2 years ago

Generating a signature with RSA alone on a long message would be too slow (presumably using cipher block chaining). Suppose we c

boyakko [2]

Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.

Computing N = PQ.

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

$\lambda (N) = \ lcm( \lambda (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)$ where $\lambda$ is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from $1$ and $gcd(E, \lambda (N) ) = 1;$ that is $E \ \ and \ \ \lambda (N)$ . D was its complex number equivalent to E (modulo $\lambda (N)$ ); that is d was its design multiplicative equivalent of E-1.

It's more evident as a fix for d provided of DE ≡ 1 (modulo $\lambda (N)$ ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.

E is eligible as a supporter of the public key.

D is retained as the personal supporter of its key.

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and $\lambda (N)$ will also be confined as they can be used in measuring D. The Euler totient operates $\varphi (N) = (P-1)(Q - 1)$ however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because $\varphi (N)$ , which can always be split into $\lambda (N)$ , and thus any D satisfying DE ≡ 1, it can also satisfy (mod $\lambda (N)$ ). It works because $\varphi (N)$ , will always be divided by $\varphi (N)$ ,. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D > $\lambda (N)$ ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D< $\lambda (N)$ . if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo $\lambda (N)$ .

As there are common threads (P− 1) and (Q – 1) which are present throughout the $N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1))$ , it's also possible, if there are any, for all the common factors $(P -1) \ \ \ and \ \ (Q - 1)$ to become very small, if necessary.

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module $\varphi (N)$ ) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.

8 0

2 years ago