The refrigerant can hold 1.92 ft³
Step-by-step explanation:
The formula to apply is that of volume
v=π *r²*h where v is volume, r is radius of cylindrical object and h is height of tubing
Finding volume of using outside diameter
v=π*7/16*7/16*12
v=49/64 *3/1 *3.14
v=7.22 ft³
Volume using inside diameter
v=π*r²*h
v=3.14*3/8*3/8*12
v=5.30 ft³
Volume the refrigerant can hold is;
7.22-5.30 = 1.92 ft³
Learn More
Volume of a cylindrical object:brainly.com/question/2665971
Keywords :conditioning,system,roll,copper tubing,refrigerant
#LearnwithBrainly
Answer:
We need the grid to figure this out
Given that you did not include the diagram showing the circle, the tangent line and the points Q, R, and S, I am going to give you the explanation to answer the question.
1) The tangent lines to a circle form a 90° angle with the radius at the point of intersection.
2) Therefore, if the point of intersection of the tangent line and the circle is named R, and the points S and Q are one the center of the circle and the other is on the line RQ, then you know that the segment SR is a radius and the line RQ is the tangent, which means that they are perpendicular, i.e. the angle QRS is measures 90°.
In this case the answer is m angle QRS = 90°.
3) Otherwise the angle is different to 90° and you need to observe the figure to conclude whether it is greater than 90°, less than 90° or there is not enough information.
Solution :
The minimum distance from Earth to the Sun is 91.4 million miles
The maximum distance is 94.5 million miles



d=92.95



Absolute Value Equation:
|x - d| = 
|x - 92.95| = 1.55
Answer: 42.84 kg
Step-by-step explanation: Lawn is 17 ft x 20 ft.
Its area is S = 17 x 20 = 340 ft²
Each ft² of lawn accumulates 1050 snowflakes/min, 1ft² = 1050 s.f./min.
As 1 hour has 60 min, the lawn accumulates 63000/hour →
1050 x 60 = 63000
1ft² = 63000s.f./hour
This way, 340 ft² of lawn will accumulate 21,420,000 s.f/hour →
340 x 63000 = 21420000
As 1 snowflake has 2mg, 21,420,000 will have 42,840,000 mg.
As 1kg = 1,000,000 mg
42,840,000/1,000,000 = 42.84 kg