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MrRissso [65]
2 years ago
14

Juan wants to change the shape of his vegetable garden from a square to a rectangle, but keep the same area so he can grow the s

ame amount of vegetables. The rectangular garden will have a length that is 2 times the length of the square garden, and the width of the new garden will be 16 feet shorter than the old garden. The square garden is x feet by x feet. What is the quadratic equation that would model this scenario?
Mathematics
2 answers:
Finger [1]2 years ago
6 0

the answer is a. x^2+(2x)(x-16)

viva [34]2 years ago
5 0
Short Answer: x^2 - 32x = 0
Square garden has a side of x
Area of the square garden is x^2

The length of the rectangle = 2x
The width is x - 16
Area of the rectangular garden is 2x(x - 16)
Area of the rectangular garden is 2x^2 - 32x

The area of the square and the rectangle must remain the same.
2x^2 - 32x = x^2    Subtract x^2 from both sides.
2x^2 - x^2 - 32x = 0

x^2 - 32x = 0       Technically this is the answer to your question.


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The first answer is 3/34 sec and the second answer is 15/34 sec.

Set up a proportion for these problems.  For the first question,
340/1 = 30/x

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Divide both sides by 340:
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For the second question,
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Answer:

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Step-by-step explanation:

Here is a step by step explanation:

https://simplisico.com/share/q/1gTpymQbmD3qwvM3GXfSxDXl

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Thus, the third angle is given by 180 - 25 - 71.97 = 83.03 degrees.

We also use the sine rule to find the third side of the triangle as follows.
\frac{\sin{A}}{a} = \frac{\sin{C}}{c} \\ \frac{\sin{25^o}}{20} = \frac{\sin{83.03^o}}{c} \\ c= \frac{20\sin{83.03^o}}{\sin{25^o}} = \frac{19.8522}{\sin{25^o}} =46.97 yds

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