An airline, believing that 5% of passengers fail to show for flights, overbooks (sells more tickets than there are seats). Suppo
se that for a particular flight involving a jumbo-jet with 267 seats, the airline sells 278 tickets.
Question 1. What is the expected number of ticket holders that will fail to show for the flight? (Use 2 decimal place in your answer.)
Question 2. What is the probability that the airline will not have enough seats for all the ticket holders who show for the flight?
Question 1. What is the expected number of ticket holders that will fail to show for the flight? (Use 2 decimal place in your answer.)
Question 2. What is the probability that the airline will not have enough seats for all the ticket holders who show for the flight?
1 answer:
Answer:
Q1. 13 passengers
Q2. 0.1756 (approx. 0.18)
Step-by-step explanation:
Q1. 267 seats are available on the plane
5% is expected to fail to show up
Hence, no of passengers expected not to show up = 267 * 0.05
= 13.35 (approx 13 passengers)
Q2. See working in the attachment as I had to explain it step by step.
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Answer:
y = 0.2x + 250
Step-by-step explanation:
let the sales be x and y be earnings
thus,
given
x₁ = $3,500 ; y₁ = $950
and,
x₂ = $2,800 ; y₂ = $810
Now,
the standard line equation is given as:
y = mx + c
here,
m is the slope
c is the constant
also,
m =
or
m =
or
m = 0.2
substituting the value of 'm' in the equation, we get
y = 0.2x + c
now,
substituting the x₁ = $3,500 and y₁ = $950 in the above equation, we get
$950 = 0.2 × $3,500 + c
or
$950 = $700 + c
or
c = $250
hence,
The equation comes out as:
y = 0.2x + 250