92 divided by 11 with remainder

which geometric series represents 0.4444... as a fraction? a) 1/4, 1/40, 1/400, 1/4,000 b) 1/40, 1/400, 1/4,000, 1/40,000 c) 4/1

xenn [34]

Answer: $\frac{4}{10}+\frac{4}{100}+\frac{4}{1,000}+\frac{4}{10,000}$

Step-by-step explanation:

The given geometric series are:

a) $\frac{1}{4}+\frac{1}{40}+\frac{1}{400}+\frac{1}{4,000}$

on simplifying in decimals, we get

$0.25+0.025+0.0025+0.00025=0.27775\neq0.4444$

b) $\frac{1}{40}+\frac{1}{400}+\frac{1}{4,000}+\frac{1}{40,000}$

on simplifying in decimals, we get

$0.025+0.0025+0.00025+0.000025=0.027775\neq0.4444$

c) $\frac{4}{10}+\frac{4}{100}+\frac{4}{1,000}+\frac{4}{10,000}$

on simplifying in decimals, we get

$0.4+0.04+0.004+0.0004=0.4444$

Thus, this geometric series represent 0.4444.

d) $\frac{1}{10}+\frac{1}{100}+\frac{1}{1,000}+\frac{1}{10,000}$

on simplifying in decimals, we get

$0.1+0.01+0.001+0.0001=0.1111\ \neq0.4444$

7 0

2 years ago

Read 2 more answers

Consider the following formula used to estimate height, h, of a seedling after w weeks since planting:

svp [43]

Answer:

Option B. $w=5h-8$

Step-by-step explanation:

we have

$h=(\frac{1}{5})w+(\frac{8}{5})$

Solve for w

That means ----> isolate the variable w

Multiply by 5 both sides to remove the fraction

$5h=w+8$

subtract 8 both sides

$5h-8=w+8-8$

$5h-8=w$

Rewrite

$w=5h-8$

4 0

2 years ago

Find each measure for the given set of data: 11, 13, 17, 20, 22, 25, 27, 31, 31, 33, Mean= Median= Range= interquartile range= I

Tresset [83]

Answer:

Mean=23

Median =23.5

Range=22

Interquartile range = 14

Step-by-step explanation:

Given set of data

11,13,17,20,22,25,27,31,31,33

Mean $=\frac{11+13+17+20+22+25+27+31+31+33}{10}$

$=\frac{230}{10}$

=23

The $(\frac{n}{2})$ th term= the 5th term

=22

The $(\frac{n}{2}+1)^{th}$ term = The $6^{th$ term

= 25

The median = $\frac{22+25}{2}$

=23.5

Range = Highest term - lowest term

=33- 11

=22

Here lower half {11,13,17,20,22}

The middle number of lower half is first quartile.

Q₁ = 17

And lower half is{25,27,31,31,33}

The middle number of upper half is third quartile.

Q₃=31

Interquartile Range =Q₃-Q₁

=31-17

=14

8 0

2 years ago

The two lines, P and Q, are graphed below: Line P is drawn by joining ordered pairs negative 8,15 and 6, negative 12. Line Q is

andreyandreev [35.5K]

Solution:

Keep in mind ,

Equation of line joining two points (a,b) and (p,q) is given by :

$\frac{q-b}{p-a}=\frac{y-b}{x-a}$

Equation of line P which is obtained by joining (- 8,15) and (6, - 12) is given by:

$\frac{y-15}{x+8}=\frac{-12-15}{6+8}\\\\ 14(y-15)=-27(x+8)\\\\ 14 y -210= -27 x - 216\\\\ 27 x+14 y+6=0$

Equation of line Q which is obtained by joining (4,16) and (-9, 10) is given by:

$\frac{y-16}{x-4}=\frac{16-10}{4+9}\\\\ 13(y-16)=6(x-4)\\\\ 13 y -208= 6 x - 24\\\\ 6 x-13 y+184=0$

Equation of line P and Q are

27 x+14 y+6=0-------(1)× 2

6 x-13 y+184=0-------(2)× 9

54 x + 2 8 y+12=0---(1)

54 x -117 y +1656=0----(2)

(1) - (2)

145 y= 1644

y=11.33,

27 x+14 y+6=0-------(1)×13

6 x-13 y+184=0-------(1)×14

351 x + 182 y + 78=0-----(1)

84 x - 182 y +2576=0----(2)

(1) + (2)

435 x + 2654=0

x = - 6.11

So, solution set is (-6.11, 11.33)

Option (C) is true. (−2, 4), because this point makes both the equations incorrect.

8 0

2 years ago

Hailey paid $13\$13 $13 dollar sign, 13 for 137 kg1\dfrac3{7} \text{ kg} 1 7 3 kg 1, start fraction, 3, divided by, 7, end fra

Colt1911 [192]

Answer:

$3.90 was the cost of salami per kilogram.

Step-by-step explanation:

The question is incomplete, so the complete question is below:

$Hailey\ paid\ \$13\ for\ 1\ 3/7\ kg\ of\ sliced\ salami.\ \\What\ was\ the\ cost\ per\ kilogram\ of\ salami?$

Now, to find the cost of salami per kilogram.

Cost of $1\frac{3}{7}$ kilogram of sliced salami = $13.

Now, to get the cost of salami per kilogram we use unitary method:

If, the cost of $\frac{10}{3}$ kilogram of salami = $13.

Then, the cost of 1 kilogram of salami = $\frac{13}{\frac{10}{3}}$

$=\frac{13}{10}\times 3$

$=\frac{39}{10}$

$=\$3.90.$

Therefore, $3.90 was the cost of salami per kilogram.

8 0

2 years ago