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padilas [110]
2 years ago
3

SUMO Some people believe that the N(555, 101)lbs distribution is not the correct model for sumo wrestlers’ weights. Their opinio

n is that the N(326, 80)lbs distribution is a better model. Manny Yarbrough, a former American sumo wrestling champion, weighed roughly 700 lbs.
If we use the N(555, 101)lbs model, would Manny’s weight be considered typical or unusually high?
i. There is a certain number that you would calculate and then use to answer the above question. Which of the following options is it?

a. (700-555)/sqrt(101) = 14.43
b. (555-700)/sqrt(101) = -14.43
c. 700/sqrt(101) = 69.65
d. (555-700)/101 = -1.44
e. (700-555)/101 = 1.44
f. 700-(3*101) = 397
g. 555-(3*101) = 252
Mathematics
1 answer:
mr Goodwill [35]2 years ago
3 0

Answer:

The answer is "Option e"

Step-by-step explanation:

use formula:

N(\mu\ , \ \sigma)= N(555,101)\\\\ \frac{N}{\mu}= 326\\\\\sigma=80\\\\\text{manny has weight}=700 \ lbs\\\\\to z-score= \frac{x-\mu}{\sigma}

                   =\frac{(700-555)}{101} \\\\ = \frac{(145)}{101} \\\\ = 1.44

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Which expression is equivalent to ( xy -6)2 for all values of x and y where the expression is defined?
hichkok12 [17]

Answer:

 ( x y -6)²  =  x² y² - 12 xy + 36            

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the expression ( x y -6)²

Apply formula (a-b)² = a² -2ab + b²

( x y -6)² = (xy)² - 2 × xy× 6 + (6)²

             = x² y² - 12 xy + 36

( x y -6)²  =  x² y² - 12 xy + 36            

4 0
2 years ago
Read 2 more answers
NEED HELP ON NUMBER 13 AND 14
Kazeer [188]

Answer:

Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.

Question 14: The club was making a loss between 11.28 and 4.88 years.

Step-by-step explanation:

Question 13:

The age group y for which the response rate R is 8 microseconds  is given by the solution of the equation

8=y^4 +2y^3 - 4y^2 -5y +14.

We graph this equation and find the solutions to be

y=1;   y=1.302;     y=-2;    y=-2.302.

Since only positive solutions for y are valid in the real world we take only those.

Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.

Question 14:

The footbal club is making a loss when p(t)

Or

t^3 -14t^2 +20t +120

We graph this inequality and find the solutions to be

t and 4.88

Since in the real world only positive values for t are valid, we take the the second solution to be true.

Thus the club was making a loss in years 4.88

5 0
2 years ago
A number cube has faces numbered 1 to 6. What is true about rolling the number cube one time? Select three options. S = {1, 2, 3
Marat540 [252]

Answer:

The correct answers are the options B. ; C. ; D.

Step-by-step explanation:

A numbered cube has face from 1 to 6.

The set S = {1, 2, 3, 4, 5, 6}.

A. If A is a subset of S, A could be {0, 1, 2}. This statement is false as A is a subset of B and A contains the element {0} which is not in S.

B. If A is a subset of S and A is given by {5, 6}. This statement is true as A elements of A are also in S.

C. If a subset A represents the complement of rolling a 5, then A = {1, 2, 3, 4, 6}. This statement is even true as A should contain all numbers from 1 to 6 except 5.

D. If a subset A represents the complement of rolling an even number, then A = {1, 3}. This statement is true as the numbers complement of an even number are 1, 3 and 5.

5 0
2 years ago
Read 2 more answers
In triangle ABC segment DE is parallel to the side AC. (The endpoints of segment DE lie on the sides AB and BC respectively).
ivanzaharov [21]

Answer:

6 dm

Step-by-step explanation:

Triangle DBE is similar to triangle ABC, so their side lengths are proportional.

DE/AC = DB/AB

The length of DB can be found from ...

DB +AD = AB

DB = AB -AD = (15 -10) dm = 5 dm

So, we can fill in the proportion:

DE/(18 dm) = (5 dm)/(15 dm)

DE = (18 dm)·(1/3) . . . . . . . . . . simplify, multiply by 18 dm

DE = 6 dm

_____

It can be helpful to draw and label a figure.

5 0
2 years ago
Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes
Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2\times 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 \times 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled \triangle AOB.

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = \dfrac{Total\ distance}{Total\ time}

\Rightarrow \dfrac{74.28}{5} = 14.86\ knots

6 0
2 years ago
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