EVELYN HAD 9 DOLLS, BUT SHE LOST 1/3RD OF THEM AT DAYCARE. HOW MANY TOTAL DOLLS WOULD EVELYN HAVE HAD IF SHE HAD NOT LOST THEM?
1 answer:
Answer:
Total Dolls would Evelyn have had if she had not lost them = 9 Dolls
Step-by-step explanation:
As given,
Total dolls Evelyn had = 9
Total dolls lost = × 9 = 3
So, Now
Evelyn had total dools after lost = 9 - 3 = 6
If she had not lost te dolls , then she had 3 dolls more
∴ we get
If she had not lost any dolls , Evelyn had total dolls = 6 + 3 = 9
So, The answer would be :
Total Dolls would Evelyn have had if she had not lost them = 9 Dolls
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Answer:
< CFE = 40°
Step-by-step explanation:
To better understand the solution, see attachment for the diagram.
Given:
BC parallel to DE
Measure of Arc BD = 58°
Measure of Arc DE = 142°
First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.
The line ST divides the arc BD and arc DE into half.
That is:
Arc SC = 1/2(arc BC) =1/2(58)
Arc SC = 29°
Arc TE = 1/2(arc DE) =1/2(142)
Arc TE = 71°
Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle
29° + Arc CE + 71° = 180°
Arc CE + 100° = 180°
Arc CE = 180-100
Arc CE = 80°
Inscribed angle = 1/2(intercepted angle)
<CFE = 1/2(Arc CE )
<CFE = 1/2(80)
< CFE = 40°
