answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Korvikt [17]
2 years ago
14

The Harris Poll tracks the favorite sport of Americans who follow at least one sport. Results of the poll show that professional

football is the favorite sport of 33% of Americans who folllow at least one sport, followed by baseball at 15%, mens college football at 10%, auto racing at 6%, mens professional basketball at 5%, and ice hockey at 5%, with other sports at 26%. Consider a survey in which 344 college undergraduates who follow at least one sport were asked to identify their favorite sport produced the following results:
Professional Football Baseball Men's college football Auto racing Men's professional basketball IceHockey OtherSports
111 39 46 14 6 20 108
Do college undergraduates students differ from the general public with regard to their favorite sports? Use x= .05.
Mathematics
1 answer:
kirill115 [55]2 years ago
4 0

Answer:

The calculated  χ²  = 20.779  falls in the critical region  χ² ≥ 14.46 so we accept the null hypothesis that all the means are equal and college undergraduates students do not differ from the general public with regard to their favorite sports.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0: the college undergraduates students do not differ from the general public with regard to their favorite sport

H0:  μ1= μ2=μ3=μ4= μ5=μ6=μ7=μ

against the claim

Ha: the college undergraduates students differ from the general public with regard to their favorite sport

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is ( Pearson goodness of fit test )

χ²= ∑ (O - E)²/ E   where O is the observed and E is the expected frequency

which has an approximate chi square distribution with 6 (n-1) d.f

4) Computations:

Under H0 , the observed frequencies are :

 Observed       Expected          (O-E)          (O-E)²                   (O-E)²/E

 111                    (0.33*344)=

                             113.52           -2.52             6.3054              0.0555

  39                      51.6               -12.6              158.76               3.0767

  46                       34.4               11.6               134.56              3.911

  14                       20.64              -6.64           44.0896           2.136

  6                        17.2                   -11.2            125.44             7.293

 20                       17.2                    2.8             7.84                 0.4558

<u> 108                       89.44                18.56           344. 4736       3.8514               </u>

<u>                               344                                                             20.779     </u>

 

5) The critical region is χ² ≥  χ² (0.025)6 = 14.45

6) Conclusion:

The calculated  χ²  = 20.779  falls in the critical region  χ² ≥ 14.46 so we reject the null hypothesis that all the means are equal and college undergraduates students do not differ from the general public with regard to their favorite sports.

You might be interested in
The improper fraction 37/6 can be changed to the mixed number​
Lana71 [14]

Answer: 6 1/6

Step-by-step explanation:

6 can go into 37 6 times

6x6=36

with 1 left over

5 0
2 years ago
A 16-inch candle is lit and burns at a constant rate of 0.8 inches per hour. Let t represent the number of hours since the candl
Tamiku [17]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

a.

The initial length of the candle is 16 inch. It also given that, it burns with a constant rate of 0.8 inch per hour.

After one hour since the candle was lit, the length of the candle will be (16 - 0.8) = 15.2 inch.

After two hour since the candle was lit, the length of the candle will be (15.2 - 0.8) = 14.4 inch. The length of the candle after two hours can also be represented by {16 - 2(0.8)}.

Hence, the length of the candle after t hours when it was lit can be represented by the function, f(t) = 16 - 0.8t. f(t) = 0 at t = 20.

b.

The domain of the function is 0 to 20.

c.

The range is 0 to 16.

8 0
2 years ago
8.5b−3.4∙(13a−3.2b)+a
Nesterboy [21]

Answer:

8.5b - 3.4(13a - 3.2b) + a = 19.4b - 43.2a

Step-by-step explanation:

It is a simple mathematical problem with multiple like terms. We can solve it by applying basic mathematical rules of multiplication and addition/subtration.

8.5b - 3.4(13a - 3.2b) + a

= 8.5b - 3.4*13a -3.4*(-3.2b) + a

= 8.5b - 3.4*13a + 3.4*3.2b + a

= 8.5b - 44.2a + 10.88 b + a

Now, only like terms can be added to each other

= (8.5b + 10.9b) + (a - 44.2a)

= 19.4b + (-43.2a)

= 19.4b - 43.2a    

8 0
2 years ago
The image shows a ray of light bending at the boundary of a glass block. According to a law of optics, = n, where n is a constan
UkoKoshka [18]
The formula for the light bend would be n1*sin i= n2 * sin r

If you use "sin (90-x)= cos x" principle, you can change the sin in the equation into
n1*sin i= n2 * sin r
n1 * cos a= n2 * cos b
n2/n1= cos a/ cos b

Assuming the n constant is the ratio of the glass compared to water then the answer would be: cos a/ cos b
3 0
2 years ago
Suppose that the concentration of a bacteria sample is 100000 bacteria per milliliter. If the concentration doubles every 2 hour
Aliun [14]

Answer:

3.85 hours

Step-by-step explanation:

We have that the model equation in this case would be of the following type, being "and" the concentration of bacteria:

y = a * e ^ (b * t)

where a and b are constants and t is time.

We know that when the time is 0, we know that there are 100,000 bacteria, therefore:

100000 = a * e ^ (b * 0)

100000 = a * 1

a = 100000

they tell us that when the time is 2 hours, the amount doubles, that is:

200000 = a * e ^ (b * 2)

already knowing that a equals 100,000

e ^ (b * 2) = 2

b * 2 = ln 2

b = (ln 2) / 2

b = 0.3465

Having the value of the constants, we will calculate the value of the time when there are 380000, that is:

380000 = 100000 * (e ^ 0.3465 * t)

3.8 = e ^ 0.3465 * t

ln 3.8 = 0.3465 * t

t = 1.335 / 0.3465

t = 3.85

That is to say that in order to reach this concentration 3.85 hours must pass

4 0
2 years ago
Other questions:
  • A praying mantis is an interesting insect that can rotate its head 180 degrees.Suppose the praying mantis at the right is 10.5 c
    13·2 answers
  • Michaela pays her cell phone service provider $49.95 per month for 500 minutes. any additional minutes used cost $0.15 each. in
    11·2 answers
  • When Θ = 5 pi over 6, what are the reference angle and the sign values for sine, cosine, and tangent?
    11·2 answers
  • The length of the hypotenuse of a right triangle is 24 inches. If the length of one leg is 8 inches, what is the approximate len
    10·2 answers
  • Chi loves to read. He can speed-read 40 pages in 3 minutes. How long should it take him to read "The Scarlet Letter," a 265- pag
    9·1 answer
  • The price of a share of one stock fell from $8.75 to $8.54. Find the percent decrease. Round your answer to the nearest tenth of
    7·2 answers
  • Which of the following groups has terms that can be used interchangeably with the others?1. Percentage, Probability, and Proport
    10·2 answers
  • Daisy works at an ice-cream parlor. She is paid $10 per hour for the first 8 hours she works in a day. For every extra hour she
    8·1 answer
  • Ann aumento 60% las cantidades de
    8·1 answer
  • Dennis is numbering the pages of his book. Page 1 is right hand,page 2 a left hand page and faces 3,a right hand page. Which two
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!