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ser-zykov [4K]
2 years ago
13

Sari estimated the quotient of 120.78 ÷ 9.9 to be 12. She said that her estimate is slightly greater than the actual answer. Is

she correct? Is her estimate reasonable? Explain.
Mathematics
2 answers:
kondor19780726 [428]2 years ago
6 0
No Sari is incorrect because 120.78/9.9 is 12.2 and 12 is not greater than 12.2
Inessa [10]2 years ago
4 0

Answer: Sari had a good estimate for the problem. But she was not correct in saying that her answer was slightly greater than the actual answer. The rounded dividend, 120, is slightly less than 120.76, and the rounded divisor, 10, is slightly greater than 9.9, so the estimate would be less than the actual quotient.

Step-by-step explanation:

Hope this helps :D

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stilt scored 5 points less than twice the number scored by dunk. together they scored 43 points. how many points were scored by
gizmo_the_mogwai [7]
Set up a system of equations:

s = 2d - 5
s + d = 43

Where 's' represents the number of points Stilt scored and 'd' represents the number of points Dunk scored.

Plug in 2d - 5 for 's' in the 2nd equation:

s + d = 43

2d - 5 + d = 43

Combine like terms:

3d - 5 = 43

Add 5 to both sides:

3d = 48

Divide 3 to both sides:

d = 16

Plug this back into any of the two equations to find 's':

s + d = 43

s + 16 = 43

Subtract 16 to both sides:

s = 27

So Dunk scored 16 points and Stilt scored 27 points.
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2 years ago
Sometimes the unit price on two sizes of the same product will be the same. When this is the case, how will different kinds of d
nadezda [96]
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4 0
2 years ago
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Which is a statistical question that you can ask to learn about your classmates’ favorite movie? What is your favorite movie? Wh
Paraphin [41]

Answer:

What is your favourite movie?

Step-by-step explanation:

The other questions are not general and would not give a useful result. We would learn a much more accurate result from the first question.

3 0
2 years ago
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What additional information is needed to prove that triangles are congruent by the SAS Postulate?
Oliga [24]

Answer: Fourth Option AB=AD


Solution:

The SAS (Side Angle Side) Postulate indicates that two triangles are congruent if they have two congruent sides and congruent the angle between these sides.

According with the figure, the triangles ABC and ACD have a congruent side (S) AC, because is a common side between the two triangles.

Additionally they have a congruent angle (A): the angle BAC in triangle ABC is congruent with the angle DAC in triangle ACD (indicated in the figure).

Then we have one congruent side (S) and one congruent angle (A). We need another congruent side to complete the SAS postulate:

The side (S) AB in triangle ABC must be congruent with the side AD in triangle ACD

Answer: Fourth option AB=AD

5 0
2 years ago
Read 2 more answers
The number of hurricanes hitting the coast of Florida annually has a Poisson distribution with a mean of 0.8. Answer the followi
slava [35]

Answer:

a) P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]

And we can find the individual probabilities like this:

P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493

P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595

P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438

And replacing we got:

P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474

b) P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595

Step-by-step explanation:

Let X the random variable that represent the number of hurricanes hitting the coast of Florida annualle. We know that X \sim Poisson(\lambda=0.8)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda=0.8

E(X)=\mu =\lambda=0.8

Part a

For this case we want this probability: P(X>2)

And for this case we can use the complement rule like this:

P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]

And we can find the individual probabilities like this:

P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493

P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595

P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438

And replacing we got:

P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474

Part b

Using the probability mass function we have:

P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595

3 0
2 years ago
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