Answer:
1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).
2.6592 grams of oxygen remain in the flask.
Explanation:
Volume of the flask remains constant = V = 2.0 L
Initial pressure of the oxygen gas = 
Initial temperature of the oxygen gas = 
Final pressure of the oxygen gas = 
Final temperature of the oxygen gas = 
Using Gay Lussac's law:
1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).
Moles of oxygen gas = n
(ideal gas equation)
Mass of 0.08310 moles of oxygen gas:
0.08310 mol × 32 g/mol = 2.6592 g
2.6592 grams of oxygen remain in the flask.
Answer:Hydrogen is placed such because it exhibits some similar characteristics of both group1 and group VII elements.
Explanation:
The reason why hydrogen is similar to group 1 metals:
#It has same valence electron and inorder achieve octet state it can lose that electron and forms H+ ion
#It acts as a good reducing agent similar to group1 metals
#It can also halides
Similarity to halogens:
#hydrogen can also gain one electron to gain noble gas configuration. It can combine with other non metals to form molecules with covalent bonding.
#It exists as diatomin molecule,H2
#Have the same electronegativity nature
#its reaction with other metal
Answer:
A titration
Explanation:
A common example of a titration is when we have an acid of unknown concentration, so we add a known volume of a base of known concentration. This process lets us determine the concentration of the acid.
By definition, a titration is a quantitative analysis, as we determine how much of an analyte is there in a sample. However, <u>there are quantitative analyzes which are not titrations</u>. This is why the most appropiate answer is<em> a titration</em>.
Answer:
The only statement about monosaccharide structure which is true is b. (Monosaccharides can be classified according to the spatial arrangement of their atoms)
Explanation:
Monosaccharides are simple sugars that are classified according to the amount of carbon atoms and based on these numbers, we can call them trioses, pentoses and hexoses. They are molecules with aldehyde (aldose) or centone (ketose) groups that have more than one alcohol function, but which do not differ in their position (OH). They do not contain N, since their general formula is Cx (H2O) x. A 6-carbon monosaccharide is called hexose, since the pentose only has 5
1) Chemical equation
Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag
2) molar ratios
1 mol Cu: 2 moles AgNO3 : 1 mol Cu (NO3)2 : 2 mol Ag
3) Convert 12. 83 * 10^23 atoms of Cu in moles
12.83 * 10 ^ 23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu
4) Use the proportions
2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag
5) Use the atomic mass of silver to convert 4.262 mol in grams
mass = number of moles * atomic mass = 4.262 mol * 107.9 g / mol = 459.9 grams
Answer: 459.9 g
