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-Dominant- [34]
2 years ago
9

Triangle FGH, with vertices F (4, -8), G (9,-4) and H (2,-3) is drawn inside a rectangle, show below. Please answer correctly !!

!! Will be marking Brianliest !!
URGENT !!!!!!!!!!!!!!!!

Mathematics
1 answer:
nata0808 [166]2 years ago
7 0

Answer:

Area=33/2

Step-by-step explanation:

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The areas of the squares created by the side lengths of the triangle are shown. Which best explains whether this triangle is a r
nikitadnepr [17]

Answer:

Based on the converse of the Pythagorean Theorem, the triangle is not a right triangle, because 9+12\neq 15

Step-by-step explanation:

The complete question in the attached figure

we know that

If the length sides of a triangle, satisfy the Pythagorean Theorem, then is a right triangle

c^2=a^2+b^2

where

c is the hypotenuse (the greater side)

a and b are the legs

In this problem

The length sides squared of the triangle are equal to the areas of the squares

so

c^2=15\ in^2  

a^2=12\ in^2

b^2=9\ in^2

substitute

15=12+9

15=21 ----> is not true

so

The length sides not satisfy the Pythagorean Theorem

therefore

Based on the converse of the Pythagorean Theorem, the triangle is not a right triangle, because 9+12\neq 15

8 0
2 years ago
Read 2 more answers
Which number line represents the following statement?<br><br> A number is more than negative five.
jarptica [38.1K]
Number Line A, well the first number line.

The open circle shows us that -5 is NOT in the solution. All the numbers greater than -5 ( x > -5) are in the solution.

Faith xoxo
3 0
2 years ago
Read 2 more answers
Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 4 − x2 − y2 and the
S_A_V [24]
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
3 0
2 years ago
Look at the figure. Which of the following segments is parallel to AB?
marusya05 [52]
I think it’s c and h
5 0
2 years ago
The radius of a cylinder is 5" and the lateral area is 70 sq. in. Find the length of the altitude. 2.8" 7" 14"
algol13
The correct question is
<span>The radius of a cylinder is 5" and the lateral area is 70pi sq. in. Find the length of the altitude.
</span>
we know that

[surface lateral area]=(2*pi*r)*height
height= [surface lateral area]/(2*pi*r)
surface lateral area=70*pi in²
r=5 in 
so
height= [70*pi]/(2*pi*5)------> 7 in

the answer is
7 in
5 0
2 years ago
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