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Sloan [31]
1 year ago
12

Annie has two equal-sized pies. She served 5/8

Mathematics
2 answers:
Dovator [93]1 year ago
6 0

Answer:

25/4

Step-by-step explanation:

........................

Fed [463]1 year ago
3 0

9514 1404 393

Answer:

 25/24

Step-by-step explanation:

Annie has 1 - 5/8 = 3/8 of the first pie left.

Annie has 1 - 1/3 = 2/3 of the second pie left.

The total fraction of pie left is ...

  3/8 + 2/3 = (3·3 +8·2)/(8·3) = 25/24 . . . of a pie left

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inna [77]

Answer: 1) Value is placed on top of the X =90

2) Value is placed on the bottom of the X =21

3)  Factored form will be (3x+5)(3x+2)

Step-by-step explanation:

Since we have given that

9x^2 + 21x + 10

As we know the quadratic form :

ax^2+bx+c=0

1) Value is placed on top of the X is given by

a\times c=9\times 10=90

2) Value is placed on the bottom of the X is given by

b=21

3) Factorised form:

We will use "Split the middle term":

9x^2 + 21x + 10\\\\=9x^2+15x+6x+10\\\\=3x(3x+5)+2(3x+5)\\\\=(3x+2)(3x+5)

Hence, Factored form will be

(3x+5)(3x+2)

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2 years ago
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Answer:

p= 7 socks

Step-by-step explanation:

gift card:$25

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p = 7

4 0
1 year ago
On a Friday evening a pizza shop had orders for 4 pepperoni, 97, and 335 cheese pizzas. If the 4 cooks each made an equal number
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Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying
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Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

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Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)'                                 [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S)                               [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S))   [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

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