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2 years ago

Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water

Physics

1 answer:

polet [3.4K]2 years ago

3 0

Answer:

7.55 g

Explanation:

Using the relation :

Δt = temperature change = (6° - 0°) = 6°

Q = quantity of heat

C = specific heat capacity = 4190 j/kg/k

1000 J = 1kJ

333 KJ = 333000 j

The quantity of ice that will melt ;

= 0.419 * 6 * 100 / 333000

= 2514000 / 333000

= 7.549 g

The mass of ice that will melt :

2.514 / 0.333

= 7.549 g

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Answer:

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similarly

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Answer:

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