Answer: a) 146 units used b) the cost of the number of units used is 3136 p.
Step-by-step explanation:
Since we have given that
First 100 units = 24 p per unit
Remaining units = 16 p per unit
New reading = 7143 units
Old reading = 6997 units
Difference between the readings would be
So, there are 146 units used.
(B) Calculate the cost of the number of units used
There are 146 units
For the first 100 units = 24 p per unit
For the remaining i.e. 146-1400 = 46 units , cost = 16 p per unit
Total cost of the number of units used is given by
Hence, a) 146 units used b) the cost of the number of units used is 3136 p.
It would be c 15/22 as the answer
Answer:
The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549
Step-by-step explanation:
We are in posessions of the sample's standard deviation. So we use the student's t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of ![1 - \frac{1 - 0.95}{2} = 0.975([tex]t_{975}](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B1%20-%200.95%7D%7B2%7D%20%3D%200.975%28%5Btex%5Dt_%7B975%7D)
). So we have T = 2.0930
The margin of error is:
M = T*s = 2.0930*0.16 = 0.3349.
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 2.92 - 0.3349 = 2.5851
The upper end of the interval is the sample mean added to M. So it is 2.92 + 0.3349 = 3.2549
The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549
Answer:
Step-by-step explanation:
hello
we need to compute the following
hope this helps
Answer:
The answer is D on edgen.
Step-by-step explanation:
D. 80
(all you do is add 40, 14 and 26 from the graph)
