Answer:
the probability that the project will be completed in 95 days or less, P(x ≤ 95) = 0.023
Step-by-step explanation:
This is a normal probability distribution question.
We'll need to standardize the 95 days to solve this.
The standardized score is the value minus the mean then divided by the standard deviation.
z = (x - xbar)/σ
x = 95 days
xbar = mean = 105 days
σ = standard deviation = √(variance) = √25 = 5
z = (95 - 105)/5 = - 2
To determine the probability that the project will be completed in 95 days or less, P(x ≤ 95) = P(z ≤ (-2))
We'll use data from the normal probability table for these probabilities
P(x ≤ 95) = P(z ≤ (-2)) = 0.02275 = 0.023
Answer:
(1,-12)
Step-by-step explanation:
d starts at (-5,-2) if you add 6 to -5 and minus -2 by 10 you will end up with (1,-12)
There are two triangles that exist in this problem. First is the given triangle ABC, witch AB = BC = 6 and AC = 8
Next is the smaller triangle formed by connecting points D and E; triangle EAD, with EA = AD = 3 and the length of DE is unknown.
Because these triangles are similar, a simple ratio may be set up in order to calculate DE.
DE / AC = EA / AB
DE = 3/6 * 8
DE = 4 units
Answer:
The 6.5-ounce cans offer the largest size at a fair cost and is the best to buy.
Step-by-step explanation:
Size of the 4.5-ounce cans of tuna in package = 4.5 × 3 = 13.5 ounce
Cost of the package= $4.32
Size of the 3.5-ounce cans = 3.5 × 4 = 14 ounce
Cost of the package= $3.92
Size of the 6.5-ounce cans = 6.5 × 5 = 32.5 ounce
Cost of the package= $9.75
The 6.5-ounce cans offer the largest size and is the best to buy.
Answer:
The hundredths place.
Step-by-step explanation:
48 is the whole number, and .061 is the decimals. As you probably know, this is the whole numbers place value.
ones, tens, hundreds, thousand, 10 thousand, 100 thousand, million...ect.
The decimal places are different
in this case the 0 is the tenths<u> </u>
the 6 is the hundredths
and the 1 is the thousandths.
Mostly, the decimal points are just with added ths to the end.
Hope this helped :D