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Maslowich
2 years ago
9

Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit was 20% and his loss on the other was 20%. On the sale of

the pipes, he:
(a) broke even, (b) lost 4 cents, (c) gained 4 cents, (d) lost 10 cents, (e) gained 10 cents
Mathematics
2 answers:
madam [21]2 years ago
6 0

Answer:

Selling price of the first pipe = $1.20

Profit = 20%

Let’s try to find the cost price of the first pipe

CP = Selling price - Profit

CP = 1.20 - 20% of CP

CP = 1.20 - 0.20CP

CP + 0.20CP = 1.20

1.20CP = 1.20

CP = 1.201.20

CP = $ 1

Selling price of the Second pipe = $1.20

Loss = 20%

Let’s try to find the cost price of the second pipe

CP = Selling price + Loss

CP = 1.20 + 20% of CP

CP = 1.20 + 0.20CP

CP - 0.20CP = 1.20

0.80CP = 1.20

CP = 1.200.80

CP = $1.50

Therefore, total cost price of the two pipes = $1.00 + $1.50 = $2.50

And total selling price of the two pipes = $1.20 + $1.20 = $2.40

Loss = $2.50 – $2.40 = $0.10

Therefore, Mr. Jones loss 10 cents.

i know that this is hard to understand so tell me if you need help

Have a great day :)

Ahat [919]2 years ago
4 0

Answer:

(d) lost 10 cents

Step-by-step explanation:

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The quotient of 9 3/4 and 5/8​
suter [353]

Answer:

15.6

Step-by-step explanation:

  1. 9\frac{3}{4} = \frac{39}{4}  
  2. Plug 39/4 in: 39/4 ÷ 5/8
  3. 39/4 ÷ 5/8 = 39/4 × 8/5
  4. 39/4 × 8/5 = 312/20
  5. \frac{312}{20} = 15.6  

I hope this helps!

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2 years ago
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A limited-edition poster increases in value each year with an initial value of $18. After 1 year and an increase of 15% per year
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Answer:

The required equation is y = 18(1.15)^x.

Step-by-step explanation:

Consider the provided information.

The Initial value of poster = $ 18

After 1 year amount of increase = $ 20.70

With the rate of 15% = 0.15

Let future value is y and the number of years be x.

y = 18(1.15)^x

Now verify this by substituting x=1 in above equation.

y = 18(1.15)^1=20.7

Which is true.

Hence, the required equation is y = 18(1.15)^x.

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2 years ago
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Finn bought a yoyo from a company that claims that, with each retraction, the string rolls up by 80% of the original length. He
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4 0
2 years ago
Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of \$65$65dollar sign, 65 along with an ho
Mandarinka [93]

Answer: (1) C. 65 + 28H < 250

(2) 6

Step-by-step explanation:

Here is the correct question:

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an

hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.

Let H represent the whole number of hours that the plumber works.

1) Which inequality describes this scenario?

Choose 1 answer:

A. 28 + 65H < 250

B. 28 + 65H > 250

C. 65 + 28H < 250

D. 65 +28H > 250

2) What is the largest whole number of hours that Anand can afford?​

Since the initial fee charged by the plumber is $65 and an hourly rate of $28, and Anand would like to spend no more than $250. This means that the addition of the initial fee plus the hourly fee based on number of hours worked will have to be less than $250. This can be mathematically expressed as:

= 65 + 28H < 250

That means option C is the correct answer.

Option B and D are incorrect because the greater sign was used but Anand doesn't want to spend more than $250 but the options denoted that he spent more than $250 which isn't correct.

2)'The largest whole number of hours that Anand can afford goes thus:

65 + 28H < 250

28H < 250 - 65

28H < 185

H < 185/28

H < 6.6

Therefore, the largest whole number of hours that Anand can afford is 6.

5 0
2 years ago
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