Software as a Service cloud model is ideal for Rita’s business. SaaS are office solutions that allow Rita’s small business to work more efficiently and in a more organized way. Most SaaS applications are used for invoicing and accounting, sales, performance monitoring, and overall planning. SaaS applications can save Rita money. They do not require the deployment of a large infrastructure at her location. As a result, it drastically reduces the upfront commitment of resources. Whoever manages SaaS’s IT infrastructure running the applications brings down fees for software and hardware maintenance. SaaS has generally been acknowledged to be safer than most on-premise software.
Answer:
The correct answer to the following question is option A. an avoidance spiral.
Explanation:
An avoidance spiral is a spiral in which parties avoid the conflicts at all cost in which leads to reducing the influence, dependence, etc. This spiral can also be destructive.
In other words, it is the only spiral in parties slowly reduces their dependence and the influence on the one and another.
Answer:
The best cloud option for Widget Corp considering the cloud computing option should be cost-effective and should not expose mission-critical applications and data to the outside world.
Is a hybrid could.
Explanation:
The reasons behind this answer are that in the first place the cloud is not going to be fully managed by a third party, but also by the IT department of Widget Corp allowing it to control its security. Also, that the cloud can be adapted to public or mainstream sources, resources, and platforms. Making it very user friendly and lowering down specific knowledge to use it.
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.
Answer:
The following code are:
public void dissolve() {
setRed(getRed()+1);
setGreen(getGreen()+1);
setBlue(getBlue()+1);
alpha+=1;
}
Explanation:
Here, we define the void type function "dissolve()" inside it, we set three function i.e, "setRed()", "setGreen()", "setBlue()" and then we increment the variable "alpha" by 1.
Inside those three mutators method we set three accessor methods i.e, "getRed()", "getGreen()" , "getBlue()" and increment these accessor by 1.
The values will not be returned by the mutator functions, the accessor will be returned the values.
