Estimate the following product in scientific notation, and then select best answer for the products power of 10.

The position of a particle moving to the right on the x-axis is given by x(t), where x(t) is measured in inches and t is measure

wlad13 [49]

Answer:

No options

Step-by-step explanation:

Knowing that V=in/min = x(t)/t and according to the graph,

V=20in/20min=in/min, so

No options since speed is not inches per minute, spedd (V) = inches over minutes

8 0

2 years ago

Read 2 more answers

7. During the Middle Ages, people often used grains, scruples, and drahms to measure the weights of different medicines. If 120

Serjik [45]

Answer:

5 drahms.

Step-by-step explanation:

From the question given above, the following data were obtained:

120 grains = 6 scruples

6 scruples = 2 drahms

300 grains (in drahms) =..?

From the above data,

120 grains = 6 scruples

6 scruples = 2 drahms

Therefore,

120 grains = 2 drahms

Thus, we can obtain 300 grains in drahms as follow:

120 grains = 2 drahms

Therefore,

300 grains = 300 grains × 2 drahms /120 grains

300 grains = (300 × 2)/120 drahms

300 grains = 5 drahms

Therefore, 300 grains is equivalent to 5 drahms.

5 0

2 years ago

Which is the smallest 0.37 0.194 0.6 0.473 0.29

wolverine [178]

0.37

0.194

0.6

0.473

0.29

the smallest digit at tenth place is 1 in 0.194, so 0.194 is the smallest here

4 0

2 years ago

Read 2 more answers

ABCD is a rectangle and A and B are the points (4,2) and (2,8) respectively. Given that the equation of AC is y=x-2, find a) Equ

Rudik [331]

A(4,2), B(2,8)

AC: y=x-2

Point point form for a line through (a,b) and (c,d) is (c-a)(y-b)=(d-b)(x-a)

AB is (2 - 4)(y - 2) = (8-2)(x-4)

-2(y - 2)=6(x-4)

y - 2 = -3(x-4)

y = -3x + 14

BC is perpendicular through B, so slope 1/3 and we calculate the constant as y-(1/3)x:

y = (1/3) x + (8 - (1/3)(2) ) = (1/3) x + 22/3

a)Answer: BC is y = (1/3) x + 22/3

C is the meet of AC and BC,

x - 2 = (1/3) x + 22/3

3x - 6 = x + 22

2x = 28

x = 14

y = x-2 = 12

Check: y = (1/3)x + 22/3 = (14+22)/3 = 36/3 = 12 good

C(14,12)

The remaining corner is D. We have A-B=D-C or

D = A+C-B+C = (4,2)+(14,12)-(2,8) = (16, 6)

b)Answer: B(2,8) [given, but asked for] C(14,12), D(16,6)

8 0

2 years ago

Jack was so frustrated with his slow laptop that he threw it out of his second story window. The height, h, of the laptop at tim

jeyben [28]

Answer:

The domain of the function is the interval [0,2.23]

see the explanation

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> the height of the laptop in units

we have

$h(t)=-16t^{2}+28t+17$

we know that

When the laptop hits the ground, the value of h(t) is equal to zero

so

For h(t)=0

$-16t^{2}+28t+17=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^{2}+28t+17=0$

so

$a=-16\\b=28\\c=17$

substitute in the formula

$x=\frac{-28(+/-)\sqrt{28^{2}-4(-16)(17)}} {2(-16)}$

$x=\frac{-28(+/-)\sqrt{1,872}} {-32}$

$x=\frac{-28(+/-)12\sqrt{13}} {-32}$

$x_1=\frac{-28(+)12\sqrt{13}} {-32}=-0.477$

$x_1=\frac{28(-)12\sqrt{13}} {32}=-0.477$ ---> is not a solution

$x_2=\frac{-28(-)12\sqrt{13}} {-32}$

$x_2=\frac{28(+)12\sqrt{13}} {32}=2.23\ sec$

therefore

The domain of the function is the interval [0,2.23]

All real numbers greater than or equal to 0 seconds and less than or equal to 2.23 seconds

$0\ sec \leq x \leq 2.23\ sec$

5 0

2 years ago