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2 years ago

13

Find the number of revolutions made by a wheel with a radius of 5 ft that traveled 633 ft. Use 3.14 for p. Round your answer to

the nearest tenth of a revolution.

1 answer:

tino4ka555 [31]2 years ago

6 0

2 x pi x 5 = 31.5 ft

633/31.5 = 20.1 revolutions

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What is 10.2719 rounded to the nearest hundreth?

Paladinen [302]

Find the number in the hundredth place
7
7
and look one place to the right for the rounding digit
1
1
. Round up if this number is greater than or equal to
5
5
and round down if it is less than
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5
.
10.27

4 0

2 years ago

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The value of a rare painting has increased each year since it was found at a garage sale. The value of the painting is modeled b

solmaris [256]

799 represents the initial value of the painting

The painting will be worth $926 after 5 years to the nearest dollar

Step-by-step explanation:

The form of the exponential function is $f(x)=a(b)^{x}$ , where

a is the initial value ⇒ (at x = 0)
b is the growth/decay factor ⇒ (rate of change)
If b > 1, then the function is growth ⇒ (increasing)
If 0 < b < 1, then the function is decay ⇒ (decreasing)

The value of a rare painting has increased each year since it was

found at a garage sale

The value of the painting is modeled by the function $f(x)=799(1.03)^{x}$

We need to know what 799 represents and what the painting will

be worth after 5 years

∵ $f(x)=799(1.03)^{x}$

∵ The form of the function is $f(x)=a(b)^{x}$

- By comparing the two forms

∴ a = 799 and b = 1.03

∵ a is the initial value at x = 0

∴ 799 represents the initial value of the painting

∵ x represents the number of years

∴ x = 5

- Substitute the value of x in the function by 5

∵ $f(5)=799(1.03)^{5}$

∴ f(x) = 926.26

∴ The painting will be worth $926 after 5 years to the nearest dollar

799 represents the initial value of the painting

The painting will be worth $926 after 5 years to the nearest dollar

Learn more:

You can learn more about the functions in brainly.com/question/10382470

#LearnwithBrainly

6 0

2 years ago

The number of calls coming per minute into a hotel reservation center is Poisson random variable with mean 3.

natima [27]

Answer:

a) 0.05

b) 0.9826

c) 0.000039308

Step-by-step explanation:

a) $P_X(0) = \frac{e^{-3}3^0}{0!} = e^{-3} = 0.05$

b) For two minutes, the mean is doubled, hence it is 6. In order to calculate the probability of al least two calls arriving, we calculate first the probability of the complementary event: At most 1 call will arrive. For that probability, we need to sum the probabilities of 0 and 1.

$P_X(0) = e^{-6}$

$P_X(1) = \frac{e^{-6}*6^1}{1!} = 6*e^{-6}$

Hence,

$P(X \geq 2) = 1-P(X < 2) = 1- 7*e^{-6} = 0.9826$

c) For five minutes the mean is 15. We need to sum the probabilities of 0, 1 and 2.

$P_X(0) = e^{-15}$

$P_X(1) = e^{15}*15$

$P_X(2) = \frac{e^{-15}*15^2}{2!} = 112.5*e^{-15}$

As a result,

$P(X \leq 2) = e^{-15}(1+15+112.5) = 0.000039308$

Practically 0

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2 years ago

YOU DONT HAVE TO DO ALL IF YOU DONT WANT TO JUST DO WHAT YOU CAN

Vikki [24]

Answer:

(Warning) Not sure this is completley correct but this is just what I did.

Part A

Does the data for Amit’s puppy show a function? Why or why not?

It does show a function because it passes the vertical line test (no two points have the same x value).

Part B

Is the relationship for Amit’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

Nonlinear because the line isn’t straight

Part C

Is the relationship between Amit’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

Increasing because it is gaining weight

Part D

Does the data for Camille’s puppy show a function? Why or why not?

Yes, it does, because each input value has a unique output value

Part E

Is the relationship for Camille’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

It is a linear function because the line has no curve, and the line is constant.

Part F

Is the relationship between Camille’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

Increasing because as the puppy gets older it gains weight.

Part G

Does the data for Olivia’s puppy show a function? Why or why not?

Yes, it does, because each input value has a unique output value. The graph attached ( which shows the data for Camille’s puppy), that each x-value (Weeks) has a unique y-value (Weight in pounds).

Therefore, based on this and keeping in mind the explanation before, you can conclude that the data for Camille’s puppy shows a function.

Part H

Is the relationship for Olivia’s puppy’s weight in terms of time linear or nonlinear? Explain your response

Yes, it linear because it’s a straight line.

Part I

Is the relationship for Olivia’s puppy’s weight in terms of time increasing or decreasing? Explain your response. Increasing. For every week that goes by, Olivia's puppy is gaining one pound. 6-5= 1 14-13= 1. Gaining a pound every week makes the puppy’s weight increase.

Part J

Which two relationships have a y-intercept and a constant rate of change?

They all have y-intercepts and only Olivia and camilles have a constant rate of change.

Part A

To compare the linear functions, you first need to find their equations. For each of the linear functions, write an equation to represent the puppy’s weight in terms of the number of weeks since the person got the puppy.

Linear equation, y=mx+b

Exponential equation, y=a(b)×

Part B

Now you can compare the functions. In each equation, what do the slope and y-intercept represent in terms of the situation?

The y-intercept in the situation is 2/6.

Part C

Whose puppy weighed the most when the person got it? How much did it weigh?

Olivia’s puppy, it weighed 5 pounds

Part D

Whose puppy gained weight the slowest? How much did it gain per week?

Olivia’s puppy gained weight the slowest because it started off with more weight but only gained around 1 pound every week.

Part E

You can also graph the functions to compare them. Using the Edmentum Graphing Tool, graph the two linear functions. Paste a screenshot of the two functions in the space provided. How could you find which puppy had a greater initial weight from the graph? How could you find which puppy gained weight the slowest?

The edmentum graphing tool is opening up I tried it more than once but, the linear graphs would be Camille puppy and olivia's. And I could tell which one had a greater weight by how much they had at week 1 and how much they gained the weeks later. I could find which puppy gained weight the slowest by looking at the weight gained and graphed.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What is the pattern in the values as the exponents increase? Powers of 2 Value 2 Superscript negative 5 StartFraction 1 Over 32

Tatiana [17]

Answer:

(D)Multiply the previous value by 2

Step-by-step explanation:

$\left|\begin{array}{c|c}$Powers of 2&Value\\2^{-5}&\frac{1}{32}\\\\2^{-4}&\frac{1}{16}\\\\2^{-3}&\frac{1}{8}\\\\2^{-2}&\frac{1}{4}\\\\ 2^{-1}&\frac{1}{2}\\\\2^{0}&1\end{array}\right|$

From the given table, we observe that the negative power of 2 reduces by 1 at each step.

$2^{-5}X2=2^{-4}\\2^{-4}X2=2^{-3}\\2^{-3}X2=2^{-2}$

Therefore, as the exponents increase, we multiply the previous value by 2 to obtain the next value.

The correct option is D.

6 0

2 years ago

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