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Sonbull [250]
2 years ago
5

Nyoko needs to be at school at 7:45 AM. It takes her 15 minutes to walk to school, 5/12 hour to eat breakfast, 0.7 hour to get d

ressed, and 0.15 hour to shower. At what time should Nyoko get up to be at school 5 minutes early?
Mathematics
1 answer:
defon2 years ago
6 0
So, she wants to be at school at 7.40 (5 mins early)

she needs:

15 mins
5/12 hours (which is \frac{5}{12} = \frac{25}{60}, so 25 mins

so far: 40 mins

then 0.7 and 0.15: we can add those, since they're in decimals: 0.85.

how many minutes is this?

\frac{85}{100} *60=  \frac{85}{10} *6=\frac{85}{5} *3=\frac{13}{1} *3=39

so 39 mins.

together with the previous 40, it's 79 minutes, which is 1 hour and 19 minutes: so she needs to wake up 1 hour and 19 minutes before 7.40 , which is

6.21!
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ASHA 777 [7]

Answer:

12\frac{2}{3}

Step-by-step explanation:

there are 4 quarters to 1 hour

3 1/6 x 4 =  

19/6 * 4 = 76/6 = 12 4/6, reduces to 12 2/3 km per hour

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2 years ago
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On Sasha's desk there are c green notebooks. The number of red notebooks on her desk is 6 less than number of green notebooks. H
aksik [14]

Sasha's desk has c green notebooks.

The number of red notebooks on her desk is c-6.

Sasha's desk has either green or red notebooks.

The total number of notebooks on Sasha's notebook is c+c-6=2c-6.



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2 years ago
The number of acres in a region cleared for farming follows the formula a = f (t) = 2t2 where t is the number of months since th
Anit [1.1K]

we are given

a=f(t)=2t^2

we can use average rate of change formula from t=a to t=b

A=\frac{f(b)-f(a)}{b-a}

Here, we are given from t=1 to t=4

so, we will get formula as

A=\frac{f(4)-f(1)}{4-1}

now, we can plug values

A=\frac{2(4)^2-2(1)^2}{4-1}

now, we can simplify it

A=10

the average rate of change in the number of acres cleared for farming between t = 1 and t = 4  is 10 acres/ month.............Answer

6 0
2 years ago
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

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2 years ago
Given: Circle X with a Radius r and circle Y with radius s Prove: Circle x is similar to circle y
lana [24]

Two figures are similar if one is the scaled version of the other.

This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.

To be more precise, you only need two steps to prove that every two circles are similar:

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Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.

Recapping, we have:

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So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.

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