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Nata [24]
2 years ago
12

Noah is ordering a taxi from an online taxi service. The taxi charges $2.50 just for the pickup and then an additional $2 per mi

le driven. How much would a taxi ride cost if Noah is riding for 4 miles? How much would a taxi ride cost that is mm miles long?
Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
8 0

Answer:

$10.50

Step-by-step explanation:

We can make an equation

2.50+2x=?

x=4 because we are riding 4 miles.

so it's 2.5+2*4=?

let's solve

2.5+8=$10.50

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Answer:

ΔLK ΔJKL

Step-by-step explanation:

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Anumeha is mowing lawns for a summer job. For every mowing job, she charges an initial fee of $10 plus a constant fee for each h
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If you are one of the first 100 people to join a new health club, you are charged a joining fee of $49. Otherwise, you are charg
Drupady [299]

Answer:

a) Total cost = 49 + 38.75m

b) Total cost = 149 + 38.75m

c) The graphs of the lines are parallel and both has slope of - 2.5

d)Difference in total cost = $132.5

Step-by-step explanation:

Total cost , TC = Initial membership fee + monthly charges

a) TC = 49 + 38.75m

b)TC = 149 + 38.75m

d) 149 + 38.75(6months) = 381.5

49 + 38.75(12months) = 514

Difference in total cost = 514 -381.5 = $132.5

7 0
2 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
Write and solve a quadratic equation for the situation below. Choose the answer that has both an equation that correctly models
Andreas93 [3]
Acceleration is:

a=g

Velocity is the integral of the above

v=gt+v0

And position is the integral of the above

h=gt^2/2+v0t+h0

You are given that v0=15ft/s and h0=0ft and let g≈-32 so

h(t)=-16t^2+15t

It will hit the ground when h(t)=0 so:

0=-16t^2+15t which is equal to

16t^2-15t=0  factor

t(16t-15)=0, since we are looking for the time other than zero...

t=15/16 of a second :)

So they obviously just rounded to one whole second.  So C.) was the correct answer.  (Although I would say they are all wrong because they didn't SAY to round the answer :P)   Haha, not trying to confuse you, the answer is most likely C. because they had the correct equation.
7 0
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