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grandymaker [24]
2 years ago
8

Which of the following quantities is likely to show more temporal autocorrelation: daily rainfall or daily temperature? Why?

Computers and Technology
1 answer:
Damm [24]2 years ago
3 0

Answer:

Temporal correlation is characterized as the association among the consecutive or sequential lags of one same variable.

As per the question, 'Daily Temperatures' are probable to display more temporal autocorrelation as compared to the daily rainfall. This is <u>because the temperatures recorded on daily basis would express the relation between the succeeding temperature values of the close locations and the locations that are farther</u>. It is more probable that places located nearer to one another would fall under the similar temperature bracket while the amount of rainfall they receive might vary.

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Most ________ are accompanied by several common utility programs, including a search program, a storage management program, and
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operating systems

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The operating systems is shortly known as OS. It is a system software which manages the software resources of the computer, computer hardware and also provides some common services for the various computer programs.

Most of the operating systems available in the market provides some common utility programs such as the search program, a backup program and a storage management program also.

Some common operating systems are : Linux, Microsoft Windows, Ubuntu, macOS, Unix, and many more.

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Write a static generic method PairUtil.minmax that computes the minimum and maximum elements of an array of type T and returns a
Gnesinka [82]

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Explanation:

The following code is written in Java. It is hard to fully create the code without the rest of the needed code including the T class and the Measurable interface. Regardless the following code can be implemented if you have that code available.

 public static T minmax(ArrayList<T> mylist) {

       T min = new T();

       T max = new T();

       for (int x = 0; x < mylist.size(); x++) {

           if (mylist.get(x) > max) {

               max = mylist.get(x);

           } else if (mylist.get(x) < min) {

               min = mylist.get(x);

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       }

       

       return (min, max);

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A clock is reading 10:27:54.0 (hr:min:sec) when it is discovered to be 4 seconds fast. Explain why it is undesirable to set it b
lara31 [8.8K]

Answer:

(a)Applications Time Stamp Events

(b)S=0.5(W-T_{skew})+T_{skew}, where T_{skew}≤W≤T_{skew}+8.

Explanation:

Some applications assume that clocks always advance, so they could timestamp events under this assumption.

In our case we have the wrong timed clock, say W and the hardware clock H which is supposed to advance at a perfect rate.

We proceed to construct a software clock such that after 8 seconds we can replace the wrong timed clock with the software clock in good conditions.

Let us denote the software clock with S.

Then, S=c(W-T_{skew})+T_{skew} where:

T_{skew}=The current Time(10:27:54) and;

c is to be found.

We already know that S=T_{skew}+4 when W= T_{skew}+8,

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S=c(W-T_{skew})+T_{skew}

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4=8c

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We obtain the formula

S=0.5(W-T_{skew})+T_{skew}, where T_{skew}≤W≤T_{skew}+8.

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