G(x)=4x^2+40x
g(x)=4(x^2+10x)
g(x)=4(x^2+10x+25)-4(25)
g(x)=4(x+5)^2-100
the missing numbers that should be filled in the blanks are:
4, 5, 100
Let me help you!
Looking at the visual, we can see five figures: KLM, 1, 2, 3, and 4.
Applying t<span>he rule T1, -4 RO, 180°(x, y) to rectangle KLMN - without even solving - just by merely observing, we can say (without a doubt) that the rectangle KLMN will most likely fall in the negative axis.
First rotation: -4 to the left.
Second rotation: -4 to the left.
Last rotation: -4 to the left making the last figure 3. <----- What we are looking for!
Therefore, the rectangle which shows the final image is figure 3 or rectangle 3.</span>
Answer:
Given:
Body mass index values:
17.7
29.4
19.2
27.5
33.5
25.6
22.1
44.9
26.5
18.3
22.4
32.4
24.9
28.6
37.7
26.1
21.8
21.2
30.7
21.4
Constructing a frequency distribution beginning with a lower class limit of 15.0 and use a class width of 6.0.
we have:
Body Mass Index____ Frequency
15.0 - 20.9__________3( values of 17.7, 18.3, & 19.2 are within this range)
21.0 to 26.9__________8 values are within this range)
27.0 - 32.9____________ 5 values
33.0 - 38.9____________ 2 values
39.0 - 44.9 _____________2 values
The frequency distribution is not a normal distribution. Here, although the frequencies start from the lowest, increases afterwards and then a decrease is recorded again, it is not normally distributed because it is not symmetric.
Answer:
x₁ > x₂
Step-by-step explanation:
Both actions imply a parable trajectories, since both are projectile shot cases.
Let´s call x₁ maximum distance in the first case
The maximum height is just in the middle of the curve, therefore x₁ the maximum horizontal distance is equal to 60 feet.
In the second case, the parable curve is modeled by:
y = x₂*( 0.08 - 0.002x₂) or y = 0.08*x₂ - 0.002*x₂²
A second degree equation, solving for x₂ and dismissing the value x₂ = 0
we get:
y = 0 ⇒ x₂*( 0.08 - 0.002x₂) = 0 x₂ = 0
And 0,08 - 0.002*x₂ = 0
- 0.002*x₂ = - 0.08
x₂ = 0.08/0.002
x₂ = 40 f
Then x₁ > x₂
