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1 year ago

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Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components . From the shipment you tak

e a random sample of 25. When sampling with replacement (so that the p = probability of success does not change), note that a success in this case is selecting a defective part. The standard deviation of this situation is?

1 answer:

Alona [7]1 year ago

6 0

Answer:

The standard deviation for the number of defective parts in the sample is 1.88.

Step-by-step explanation:

The sample is with replacement, which means that the trials are independent, and thus, the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

68 defective out of 400:

This means that $p = \frac{68}{400} = 0.17$

From the shipment you take a random sample of 25.

This means that $n = 25$

Standard deviation for the number of defective parts in the sample:

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{25*0.17*0.83} = 1.88$

The standard deviation for the number of defective parts in the sample is 1.88.

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Answer:

a

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Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

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substituting the value

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By standardizing the normal approximation we have that

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