Answer: 0.07
Step-by-step explanation:
in the group, we can have only 4 persons.
we have 8 boys, and 6 girls.
We want to find the probability that in the comite we have only boys.
Ok, for the first selection, the probability of selecting a boy is equal to the number of boys divided the total number of the group ( 8 + 6 = 14) this is
p1 = 8/14.
For the second selection we do the same, but we already slected a boy, so now the number of boys is 7, and the total number of posibilities is 13.
p2 = 7/13.
for the third selection we do the same, in this case the probability is
p3 = 6/12
for the fourth selection the probability will be:
p4 = 5/11
The joint probability, of all the events happening at the same time, is equal to the product of the singular probabilities:
P = p1*p2*p3*p4 = (8/14)*(7/13)*(6/12)*(5/11) = 0.07
