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Naddika [18.5K]
2 years ago
9

a horizontally laid standard weight pipe has a diameter of 10 inches and is 12 feet long. The pipe is filled 9 inches high with

water. How many gallons of water does the pipe hold? (Round your answer to the nearest gallon.) Please help.

Mathematics
2 answers:
AnnyKZ [126]2 years ago
5 0

Answer:

<h2>A</h2>

Step-by-step explanation:

Eduardwww [97]2 years ago
4 0

Answer:

d isósceles hijo muy graciosa ya no me acuerdo de nada y tu q ases hablas con el

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6.50 + 15.75*2 = 38

2.25*2 + 7.25*2 = 19

38 + 19 = 57

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What is the coefficient of the term 12p in the expression 12p+9q​
Tju [1.3M]

Answer:

12

Step-by-step explanation:

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What value of x would make KM ∥ JN?
stepan [7]

Answer:

x = 10

Step-by-step explanation:

By the converse of the side-splitter theorem, if \dfrac{JK}{KL}= \dfrac{NM}{ML} , then KM ∥ JN.

Substitute the expressions into the proportion:

\dfrac{x-5}{x}= \dfrac{x-3}{x+4}

Cross-multiply:

(x – 5)(x+4) = x(x – 3).

Distribute:

x(x) + x(4) - 5(x) - 5(4) = x(x) + x(-3).

Multiply and simplify:

x^2 +4x- 5x - 20 = x^2-3x\\-x-20=-3x\\$Collect like terms$\\-x+3x=20\\2x=20\\$Divide both sides by 2\\x=10

Solve for x: x = 10

Therefore, the value of x that would make KM parallel to JN is 10.

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1 year ago
A store sold a certain brand of jeans for $38 one day, the store sold 6 pair of jeans of that brand. How much did the 6 pairs of
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NEED HELP ON NUMBER 13 AND 14
Kazeer [188]

Answer:

Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.

Question 14: The club was making a loss between 11.28 and 4.88 years.

Step-by-step explanation:

Question 13:

The age group y for which the response rate R is 8 microseconds  is given by the solution of the equation

8=y^4 +2y^3 - 4y^2 -5y +14.

We graph this equation and find the solutions to be

y=1;   y=1.302;     y=-2;    y=-2.302.

Since only positive solutions for y are valid in the real world we take only those.

Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.

Question 14:

The footbal club is making a loss when p(t)

Or

t^3 -14t^2 +20t +120

We graph this inequality and find the solutions to be

t and 4.88

Since in the real world only positive values for t are valid, we take the the second solution to be true.

Thus the club was making a loss in years 4.88

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