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GaryK [48]
1 year ago
8

Using your newspaper or another source, collect data on the high (or low) temperature and the day of the week for your city for

one month. After gathering the data, complete the tasks listed below:
I. Construct a chart like the sample in the discussion. Try to have no fewer than five class intervals. "Class interval" refers to the number of categories a type of data could fall into (e.g., 70-79 degrees, 80-89 degrees, etc.).

II. Compute the probability that an observation picked at random will be a Saturday observation.

III. Repeat number two for the remaining days of the week.

IV. Use the chart in the discussion to answer these questions:

What is the probability a day in the 70s is a Monday?
Which set forms the intersection of Tuesdays in the 80s?
What is the probability an observation picked at random is both a Sunday and more than 90 degrees?
V. Construct a histogram to display the temperature frequencies for the month. (Use temperature class intervals and totals.)

VI. Pretend that you are working for the tourist bureau for your city. Which measure of central tendency (mean, median, mode) would you use in advertising to attract tourists. Justify your answer.
Mathematics
1 answer:
Lilit [14]1 year ago
4 0

Answer:

probability of any particular day being Thursday is

1

7.we have 7 probabilitiesas there are 7 days in a week we of which only one event thursday is 1 7.

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28.09 for both including taxes

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A company produces canned tomatoes. They want the height h of each can to be twice the diameter d. Enter an equation for the sur
lutik1710 [3]

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The equation is:

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Please see the attached files for explanation

5 0
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3400 dollars is placed in an account with an annual interest rate of 8.25%. How much will be in the account after 25 years, to t
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2 years ago
Consider the curve y=4x-x^3 and the chord AB joining points A(-3, 15) and B(2, -15) on the curve. Find the x- and y-coordinates
Elis [28]
We are asked to find the coordinates of the points where the slope of the curve is equal to the slope of the chord AB. We are given the coordinates of A and B. We can use these and the slope formula to find the slope of the chord.

Recall the slope formula is: m= \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }
We label the points as follows (note that you could change the way you label the points as you will get the same slope regardless of what point is designated with the 1s and which is designated with the 2s).
A=( x_{1} , y_{1)}=(-3,15)
B=( x_{2} , y_{2}=(2,-15)
Plugging these into the slope formula yields: m= \frac{-15-15}{2--3 }= \frac{-30}{5} =-6
The slope of the chord is -6


Next consider the curve y=4x- x^{3}. We can find the slope of the curve by taking the first derivative. Thus, the slope of the curve is given by: y^{'} =4-3 x^{2}

Let us set the slope of the curve equal to -6 to find the points (x,y) where the chord and the curve have the same slope.

That is, -6=4-3 x^{2}
3 x^{2} =10
x^{2} = \sqrt{ \frac{10}{3} }
x= \sqrt{ \frac{10}{3} },x= -\sqrt{ \frac{10}{3} }

We now have the x-coordinates of the points at which the slope of the chord equals that of the curve. To find the y-coordinates we substitute the values we found for x in the original equation as follows:

y=4( \sqrt{ \frac{10}{3} }) -( \sqrt{ \frac{10}{3} }) ^{3} =4(  \frac{10}{3}) ^{ \frac{1}{2} }-( \frac{10}{3}) ^{ \frac{3}{2} }
and
y=4( -\sqrt{ \frac{10}{3} }) -(- \sqrt{ \frac{10}{3} }) ^{3} =-4( \frac{10}{3}) ^{ \frac{1}{2} }+( \frac{10}{3}) ^{ \frac{3}{2} }

Thus the two points we seek (x,y) are:
( \sqrt{ \frac{10}{3} }, 4( \frac{10}{3}) ^{ \frac{1}{2} }-( \frac{10}{3}) ^{ \frac{3}{2} } )
and
( -\sqrt{ \frac{10}{3} }, -4( \frac{10}{3}) ^{ \frac{1}{2} }+( \frac{10}{3}) ^{ \frac{3}{2} } )


4 0
2 years ago
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