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2 years ago

There are 1024 bytes in a kilobyte. Write an expression that describes the number of bytes in a computer chip with n kkilobyte

Mathematics

1 answer:

Artyom0805 [142]2 years ago

4 0

Step-by-step explanation:

1024 bytes = 1 kb

n kb = 1024 × n b

Where n is a positive number

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A study is being conducted in which the health of two independent groups of ten policyholders is being monitored over a one-year

uysha [10]

Answer:

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that $p = 0.8$ .

10 students, so $n = 10$

We have to find:

$P(X \geq 9) = P(X = 9) + P(X = 10)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684$

$P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074$

$P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2684 + 0.1074 = 0.3758$

0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that $p = 0.3758$

Two groups, so $n = 2$

We have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691$

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

5 0

2 years ago

Read 2 more answers

An airplane flew at an average rate of 600 miles per hour from Tokyo to Seattle. Because of a strong headwind, the average rate

Dvinal [7]

600t = 480(18 – t) should be it

5 0

2 years ago

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You put $350 per month in an investment plan that pays an APR of 3.5% compounded monthly. How much will you have after

melamori03 [73]

Answer: B.

Step-by-step explanation: TVM Solver Equation:

N = 216 (12 x 18 years)

I% = 3.5

PV = 0

PMT = - $350

FV = 105,106.7593

P / Y = 12 (months)

C / Y = 12

PMT: END

8 0

2 years ago

According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?

scoundrel [369]

we have

$f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3$

we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

$x=\frac{p}{q}$

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

in this problem

the constant term is equal to $3$

and the first monomial is equal to $15x^{11}$ -----> coefficient is $15$

possible values of p are $1, and\ 3$

possible values of q are $1, 3, 5, and\ 15$

therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-) $\frac{1}{15}$ ,(+/-) $\frac{1}{5}$ ,(+/-) $\frac{1}{3}$ ,(+/-) $\frac{3}{5}$ ,(+/-) $1$ ,(+/-) $3$

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2 years ago

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Match each operation involving f(x) and g(x) to its answer.

galben [10]

F(x)=1-x² and g(x)=√(11-4x)

(g+f)(2)=>

1-(2)²+√(11-4(2))

=√3-3

(f/g)(-1)

(1-(-1)²)/(√(11-4(-1))

=0

(g-f)(-1)

√(11-4*-1)-(1-(-1)²

=√15

(g×f)(2)

1-(2)²×√(11-4(2))

-3√3

8 0

2 years ago