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Tanya [424]
2 years ago
6

Define a function print_feet_inch_short(), with parameters num_feet and num_inches, that prints using ' and " shorthand. End wit

h a newline. Remember that print() outputs a newline by default. Ex: print_feet_inch_short(5, 8) prints:
5' 8"
Hint: Use \" to print a double quote.


''' Your solution goes here '''

user_feet = int(input())
user_inches = int(input())

print_feet_inch_short(user_feet, user_inches) # Will be run with (5, 8), then (4, 11)
Computers and Technology
2 answers:
Crazy boy [7]2 years ago
4 0

def print_feet_inch_short(num_feet, num_inches):

#function named print_feet_inch_short takes in two arguments.

print(str(num_feet)+"'",str(num_inches)+"\"")

#output the feet and inch value supplied with the shorthand sign of feet and inch using string concatenation.

num_feet = int(input())

#allows user to specify a feet value and stores it in num_feet

num_inches = int(input())

#allows user to specify an inch value and stores it in num_inch

print_feet_inch_short(num_feet, num_inches)

#calling the function with the number of feets and inches given by user.

Learn more : brainly.com/question/18318709

tiny-mole [99]2 years ago
4 0

Program Explanation:

  • Declaring method "print_feet_inch_short" that takes two variable "num_feet and num_inches".
  • Inside the method parameter variable is used that converts the value into the string and prints its value.
  • Outside the method, a parameter variable is declared that uses an input method with the int method that takes an integer value.
  • calling the method by passing parameter value.

Program:

def print_feet_inch_short(num_feet, num_inches):# defining a method print_feet_inch_short which takes two parameters.

   print(str(num_feet)+"'",str(num_inches)+"\"")# using print method that converts parameters value into string  

num_feet = int(input())# defining num_feet variable input integer variable

num_inches = int(input())# defining num_inches variable input integer variable

print_feet_inch_short(num_feet, num_inches)#calling method

Output:

Please find the attached file.

Learn more:

brainly.com/question/14637323

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For the (pseudo) assembly code below, replace X, Y, P, and Q with the smallest set of instructions to save/restore values on the
Dimas [21]

Answer:

Explanation:

Let us first consider the procedure procA; the caller in the example given.

  Some results: $s0,$s1,$s2, $t0,$t1 and $t2 are being stored by procA. Out of these registers, few registers are accessing by procA after a call to procB. But, procB might over-write these registers.

       Thus, procA need to save some registers into stack first before calling procB, .

      only $s1,$t0 and $t1 are being used after return from procB in the given example,

       Caller saves and restores only values in $t0-$t9, according to MIPS guidelines for caller-saved and callee-saved registers, .

       Thus, procA needs to save only $t0 and $t1.

    jal instruction overwrites the register $ra by writing the address, to which the control should jump back, after completing the instructions of procB, when procB is called,.

       Therefore, procA also need to save $ra into stack.

 ProcA is writing new values into $a0,$a2, procA must save $a0 and $a1 first before calling procB, .

     In the given example, after return from procB, only $a0 is being used. It is therefore enough to save $a0.

   Also, procA needs to save frame pointer, which points the start of the stack space for each procedure.

       Generally, as soon as the procedure begins, frame pointer is set to the current value of the stack pointer,.

Let us consider the procedure procB; the callee in the given example.

 The callee is responsible for saving values in $s0-$s7 and restoring them before returning to caller, this is according to MIPS guidelines for caller-saved and callee-saved registers,

   procB is expected to over-write the registers $s2 and $t0. Nonetheless, in the first two lines, procB might over-write the registers $s0 and $s1.

   Thus, procB is responsible for saving and restoring $s0,$s1 and $s2.

X:

We need to create space for 5 values on the stack since procA needs to save $a0,$ra,$t0,$t1 and $fp(frame pointer), . Each value(word) takes 4 bytes.

$sp = $sp – 20 # on the stack, create space for 5 values

sw $a0, 16($sp) # store the result in $a0 into the memory address

               # indicated by $sp+20

sw $ra, 12($sp) # save the second value on stack

sw $t0, 8($sp) # save the third value on stack

sw $t1, 4($sp) # save the fourth value on stack

sw $fp, 0($sp) #  To the stack pointer, save the frame pointer

$fp = $sp      #  To the stack pointer, set the frame pointer

Y:

lw $fp, 0($sp) #  from stack, start restoring values

lw $t1, 4($sp)

lw $t0, 8($sp)

lw $ra, 12($sp)

lw $a0, 16($sp)

$sp = $sp + 20 # decrease the size of the stack

P:

$sp = $sp – 12 #  for three values, create space on the stack

sw $s0, 0($sp) # save the value in $s0

sw $s1, 0($sp) # save the value in $s1

sw $s2, 0($sp) # save the value in $s2

Q:

lw $s0, 0($sp) #  from the stack, restore the value of $s0

lw $s1, 0($sp) #  from the stack, restore the value of $s1

lw $s2, 0($sp) #  from the stack, restore the value of $s2

$sp = $sp + 12 # decrease the stack size

8 0
2 years ago
Publication of flaws in encryption used for copy protection is a potential violation of: A. HIPAA B. U.S. Commerce Department re
djyliett [7]

Answer:

Option C (DMCA) would be the correct choice.

Explanation:

  • DMCA is designed to govern electronic channels and tackle the problems the online revolution confronts regarding copyright.
  • DMCA's mission seems to be to accommodate the rights of intellectual property producers and investors and investigate anything other than a copyrighted material that really occurs throughout the digital environment.

The other given choice are not related to the given content. So that option C is the right one.

6 0
2 years ago
In a Diffie-Hellman Key Exchange, Alice and Bob have chosen prime value q = 19 and primitive root a = 10. If Alice's secret key
34kurt

Answer:

a) 6

b) 11

c) 11

Explanation:

Given

Prime value q =n= 19

primitive root (a) =10

Alice secret key = 4

Bob secret key = 6

a) The value Alice Sends to Bob

a​​​​​Private key of Alice mod n

= 10^4 mod 19

= 10000 mod 19

=6

b)The value Bob sends to Alice

a​​​​​Private key of Bob mod n

= a​​​​​​3​​​​​ mod n

= 10^6 mod 19

=1000000 mod 19

= 11

c)

Both the parties calculate the value of secret key at their respective side.

secret key obtained by Alice

= 11

secret key obtained by Bob

= 11

Finally, both the parties obtain the same value of secret key.

The value of common secret key = 17

6 0
2 years ago
Create an array w with values 0, 0.1, 0.2, . . . , 3. Write out w[:], w[:-2], w[::5], w[2:-2:6]. Convince yourself in each case
larisa86 [58]

Answer:

w = [i/10.0 for i in range(0,31,1)]

w[:]  = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 3.0]

w[:-2] = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8]

w[::5]= [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0]

w[2:-2:6] = [0.2, 0.8, 1.4, 2.0, 2.6]

Explanation:

List slicing (as it is called in python programming language ) is the creation of list by defining  start, stop, and step parameters.

w = [i/10.0 for i in range(0,31,1)]

The line of code above create the list w with values 0, 0.1, 0.2, . . . , 3.

w[:]  = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 3.0]

since start, stop, and step parameters are not defined, the output returns all the list elements.

w[:-2] = [0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8]

w[:-2] since  stop is -2, the output returns all the list elements from the beginning to just before the second to the last element.

w[::5]= [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0]

w[::5] since  step is -2, the output returns  the list elements at index 0, 5, 10, 15, 20, 25,30

w[2:-2:6] = [0.2, 0.8, 1.4, 2.0, 2.6]

the output returns the list elements from the element at index 2  to just before the second to the last element, using step size of 6.

6 0
2 years ago
Michael has increased the contrast of the given picture. Which feature or menu option of a word processing program did he use?
Kitty [74]
Artistic effects under design?
8 0
2 years ago
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